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2 years ago

PLEASE CHECK MY ANSWERS!! 30 POINTS!

Mathematics

1 answer:

Alenkasestr [34]2 years ago

5 0

From what I’m thinking, I’m sure they’re all correct.

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PLEASE HELP FAST!!!

worty [1.4K]

Answer: a is your answer hope this helped

plz make brainly

Step-by-step explanation:

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2 years ago

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Help please Right angle triangle

baherus [9]

Answer:

h ≈ 11.9

Step-by-step explanation:

Since the triangle is right we can use the cosine ratio to find h

cos24° = $\frac{adjacent}{hypotenuse}$ = $\frac{h}{13}$

Multiply both sides by 13

13 × cos24° = h

⇒ h = 11.9 cm ( to 1 dec. place )

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3 years ago

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Find the measure of 41. s 839 41 41 = [?]

Mila [183]

<1=97°

steps:

<1+83=180 co interior angle

<1=180-83=97°

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2 years ago

What is 108% of 112?

vovangra [49]

120.96! You can round that if you'd like.

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3 years ago

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If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

7 0

2 years ago