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kramer
2 years ago
5

PLEASE CHECK MY ANSWERS!! 30 POINTS!

Mathematics
1 answer:
Alenkasestr [34]2 years ago
5 0
From what I’m thinking, I’m sure they’re all correct.
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PLEASE HELP FAST!!!
worty [1.4K]

Answer: a is your answer hope this helped

plz make brainly

Step-by-step explanation:

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2 years ago
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Help please <br> Right angle triangle
baherus [9]

Answer:

h ≈ 11.9

Step-by-step explanation:

Since the triangle is right we can use the cosine ratio to find h

cos24° = \frac{adjacent}{hypotenuse} = \frac{h}{13}

Multiply both sides by 13

13 × cos24° = h

⇒ h = 11.9 cm ( to 1 dec. place )

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3 years ago
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Find the measure of 41.<br> s<br> 839<br> 41<br> 41 = [?]
Mila [183]

<1=97°

steps:

<1+83=180 co interior angle

<1=180-83=97°

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3 years ago
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If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
2 years ago
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