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Evgesh-ka [11]
3 years ago
13

Simplify the expression. 7(6x – 4) + 1

Mathematics
2 answers:
makkiz [27]3 years ago
7 0

Answer:

42x -27

Step-by-step explanation:

we apply distributive property:

7(6x – 4) + 1

7*6x - 7*4 +1

42x - 28 +1

42x -27

umka21 [38]3 years ago
3 0

Answer:

42x-27

Step-by-step explanation:

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Why was it helpful in the paper ball situation helpful in the paper ball situation to rewrite the expression to determine specif
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Answer:

Step-by-step explanation:

I'm not sure I know what the paper ball situation is, but I can tell you that especially when working with a set formula in physics, math or chemistry (I'd include biology if I knew any biology) that it is a good idea to write down your givens.

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I just looked up the Paper Ball Situation. This is a wonderful piece of physics. It immediately opened up all sorts of treasures once they experimenters thought of using tin foil. Givens are a necessity in such an experiment.

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3 years ago
Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
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Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

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AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

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Answer:

The system  that represent the scenario is

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The solution in the attached figure

Step-by-step explanation:

Let

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x+y\leq500 ------> inequality A

215x+615y\leq 187,500 -----> inequality B

using a graphing tool

the solution is the shaded area in the attached figure

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Answer:

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Step-by-step explanation:

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