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3 years ago

Help pls my life depends on it

Mathematics

1 answer:

ser-zykov [4K]3 years ago

8 0

The answer is 5 because you would do rise over run 50/10 which simplifies to 5

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Please help on this

satela [25.4K]

Answer:

Step-by-step explanation:

everyone likes 21

hope this helped

5 0

3 years ago

I need solving 4.8 (x+4)=2.6

victus00 [196]

<span>4.8 (x+4)=2.6
Use distributive property
4.8x + 19.2= 2.6
Subtract 19.2 from both sides
4.8x = -16.6
Divide 4.8 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: x = -3.458</span>

7 0

3 years ago

Read 2 more answers

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points) Write y

mihalych1998 [28]

Start by looking at simplifying the smaller problems

anything to the power zero is 1 $6^0 = 1$

next apply the power of a power rule... multiply the powers

$(2^8\times 3^{-5} \times 1 )^{-2} = 2^{8\times -2}\times 3^{-5 \times -2}$

which becomes

$2^{-16}\times 3^{10}$

4 0

3 years ago

A certain circuit board consists of two resistors, green and red. The circuit board manufacturer has two huge bins filled with t

Lesechka [4]

Answer:

(a) 0.675

(b) 0.3

Step-by-step explanation:

$P(R) = 90\% = 0.9$ (Probability of functional red)

$P(\sim R) = 90\% = 1 - 0.9 = 0.1$ (Probability of non-functional red)

$P(G) = 75\% = 0.75$ (Probability of functional green)

$P(\sim G) = 1 - P(G) = 1 - 0.75 = 0.25$ (Probability of non-functional green)

(a) The probability the board is functional is the probability that the red and the green resistors are functional.

$P(\text{board is functional}) = P(R\cap G) = P(R) \times P(G) = 0.9\times0.75 = 0.675$

(b) The probability that exactly one of the resistors chosen is functional is the probability that either red is functional and green is not or green is functional and red is not.

$P(\text{exactly one is functional}) = P((R\cap \sim G) \cup (G\cap \sim R))$

$P(\text{exactly one is functional}) = P(R\cap \sim G) + P(G\cap \sim R) = (P(R) \times P(\sim G)) + (P(G) \times P(\sim R))$

$P(\text{exactly one is functional}) = (0.9 \times 0.25) + (0.75 \times 0.1) = 0.225 + 0.075 = 0.3$

6 0

4 years ago

Read 2 more answers

Question 3

eimsori [14]

I can’t see the graph so I’m not sure

8 0

3 years ago