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2 years ago

Use the formula for compound interest to find A.

Mathematics

1 answer:

Crank2 years ago

4 0

Easy peasy
A=20,000(1+0.13)^2
A=20,000(1.13)^2
A=20,000(1.2769)
A=25538

A is $25,538

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Whats is the anwser to twelve times twenty

balandron [24]

Answer:240

Step-by-step explanation:

120

× 12

------

240

5 0

2 years ago

How long would it take me to earn 139.50 of interest at a 6% interest rate if I started with 930

Natali [406]

139.50/55.8=t t=2.5 yrs simple interest

3 0

2 years ago

What is the distance across the lake?

vredina [299]

Given:

Height of right triangle = 9 mi

Hypotenuse = 17.5 mi

Base of right triangle = Distance across lake

To find:

The distance across the lake.

Solution:

Using Pythagoras theorem:

In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.

$\Rightarrow 9^2+base^2=(17.5)^2$

$\Rightarrow 81+base^2=306.25$

Subtract 81 from both sides.

$\Rightarrow 81+base^2-81=306.25-81$

$\Rightarrow base^2=225.25$

Taking square root on both sides.

⇒ base = 15

The distance across the lake 15 mi.

5 0

3 years ago

How do you subtract rational expressions without a common denominator?

zubka84 [21]

You would have to make common denominators
consider a/b,c/d in Q
then a/b - c/d = ad/db - cb/bd = (ad-cb)/db for all a,b,c,d in R, exclude b,d=0
i.e. 1/2 - 1/4
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4 0

2 years ago

A single die is rolled. Find the probability of rolling an oddnumber or a number less than 6.

mina [271]

Given

A single die is rolled.

To find the probability of rolling an odd number or a number less than 6.

Explanation:

It is given that,

A single die is rolled.

Then, the sample space is,

$\begin{gathered} S=\lbrace1,2,3,4,5,6\rbrace \\ n(S)=6 \end{gathered}$

Let A be the event of getting an odd number.

Then,

$\begin{gathered} A=\lbrace1,3,5\rbrace \\ n(A)=3 \end{gathered}$

Let B be the event of getting a number less than 6.

Then,

$\begin{gathered} B=\lbrace1,2,3,4,5\rbrace \\ n(B)=5 \end{gathered}$

Also,

$\begin{gathered} A\cap B=\lbrace1,3,5\rbrace \\ n(A\cap B)=3 \end{gathered}$

Therefore,

$\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{n(A\cap B)}{n(S)} \\ =\frac{3}{6}+\frac{5}{6}-\frac{3}{6} \\ =\frac{3+5-3}{6} \\ =\frac{5}{6} \end{gathered}$

Hence, the answer is 5/6.

5 0

6 months ago

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