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lara [203]
3 years ago
13

A number is 6 greater than 1/2 another number. If the sum of the numbers is 21, find the numbers

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

Answer:

x=11, y=10

Step-by-step explanation:

x= 6+ (1/2)y

x+y=21

substitute the first equation into the second equation:

(6+ (1/2y)) + y =21

to get:

y=10

then to find x:

x+ 10 = 21

x=11

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Answer:

Step-by-step explanation:

= 4 + (-2)/ -3 + 3

= 4 - 2/ -3 + 3

= 2/0 If the denominator is 0, the value is undefined.

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2 years ago
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A recipe for 6 dozen cookies calls for 3/4 cup of sugar. How much sugar is needed to make 4 dozen cookies? pls show all work and
Paraphin [41]
So if 6 dozen cookies needs 3/4 cup of sugar, and we need to know how much sugar is needed to make 4 dozen, then find how much of 6 dozen 4 dozen is.

To do this, put it as a fraction:

4 dozen / 6 dozen, or 4/6, which is 2/3.

Since conveniently it calls for 3/4 cup of sugar, we can multiply that by 2/3, and we'll get 6/12, or 1/2.

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4 0
3 years ago
Find the a26 arithmetic sequence: -15,-35,-55,-75<br> -515 <br> 460 <br> -490
Vlad [161]

Step-by-step explanation:

<h3><u>QU</u><u>ESTION</u><u>:</u><u>-</u></h3>

<u>Fin</u>d 26th term of the A.P --15,-35,-55,-75...

<h3><u>Solu</u><u>tion</u><u>:</u><u>-</u></h3>

First term=a=-15

Common Difference=d=-20

We know that

\boxed{\sf a_n=a+(n-1)d}

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15+(26-1)(-20)

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15+25(-20)

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15+(-500)

\\ \:\:\:\:\sf {:}\dashrightarrow a_{26}=-15-500

\\ \:\:\:\:\sf {:}\dashrightarrow {\boxed{\bf a_{26}=-515}}

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula
dsp73
<h3>Solution:</h3>

( \sqrt{2}  + 1)(5 +  \sqrt{2}) \\  =  \sqrt{2}  (5 +  \sqrt{2} ) + 1(5 +  \sqrt{2} ) \\  = 5 \sqrt{2}  + 2 + 5 +  \sqrt{2}  \\  = 7 + 6 \sqrt{2}

<h3>Answer:</h3>

7 + 6√2

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2 years ago
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tangare [24]

Answer:

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Step-by-step explanation:

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