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3 years ago

A number is 6 greater than 1/2 another number. If the sum of the numbers is 21, find the numbers

Mathematics

1 answer:

Anna71 [15]3 years ago

6 0

Answer:

x=11, y=10

Step-by-step explanation:

x= 6+ (1/2)y

x+y=21

substitute the first equation into the second equation:

(6+ (1/2y)) + y =21

to get:

y=10

then to find x:

x+ 10 = 21

x=11

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4.9t^2-2.78t-1.15=0 what is the value of T

zzz [600]

Answer:

t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

Step-by-step explanation:

Solve for t:

4.9 t^2 - 2.78 t - 1.15 = 0

4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:

(49 t^2)/10 - (139 t)/50 - 23/20 = 0

Multiply both sides by 10/49:

t^2 - (139 t)/245 - 23/98 = 0

Add 23/98 to both sides:

t^2 - (139 t)/245 = 23/98

Add 19321/240100 to both sides:

t^2 - (139 t)/245 + 19321/240100 = 75671/240100

Write the left hand side as a square:

(t - 139/490)^2 = 75671/240100

Take the square root of both sides:

t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

3 0

3 years ago

Plz help!............

prisoha [69]

Answer:

Step-by-step explanation:

B/c 0 is included in the range since it the origin of the graph and it then goes to negative infinity. This is why y has to be less than equal to 0 which means 0 is included and graph goes to negative infinity.

7 0

3 years ago

Read 2 more answers

Solve for x and explain

galben [10]

Since the two lines are parallel, the angle labeled 130 is congruent to the angle labeled x+ 136 so you can set them equal to each other

130 = x + 136
subtract 136 from both sides

x = -6

4 0

3 years ago

Read 2 more answers

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

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3 years ago

If f(x) = 2x² + 5, then what is the remainder when f (x) is divided by x – 10?

photoshop1234 [79]

Answer:

Step-by-step explanation:

x - 10 = 0

x = 10

f(10) = 2*10² + 5 = 2*100 + 5 = 200 + 5

= 205

Remainder = 205

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3 years ago