Solve this equation 4+4|2x−1|=12.

2 answers:

3 0

Step 1: 8|2x-1| = 12
step 2: 16x-8 = 12
step 3: 16x =12+8
step 4: 16x = 20
divide both sides by 16
step 5: x = 5/4 or 1 1/4

satela [25.4K]2 years ago

3 0

Answer:

x=1.5 or3/4

Step-by-step explanation:

using bodmas

remove the bracket: 4+4=(2x-1)=12

4+8x-4=12

8x=12+4-4

8x=12

x=3/2 or 1.5

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To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

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$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$