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Juli2301 [7.4K]
3 years ago
15

HELPPPPPP!!

Mathematics
1 answer:
AlekseyPX3 years ago
7 0

Answer:

In 6 different ways can the three students form a set of class officers.

Step-by-step explanation:

There are 3 people Leila, Larry, and Cindy and 3 positions president, vice-president, and secretary.

We need to find In how many different ways can the three students form a set of class officers.

This problem can be solved using Permutation.

nPr = n!/(n-r)! is the formula.

Here n = 3 and r =3

So, 3P3 = 3!/(3-3)!

3P3 = 3!/1

3P3 = 3*2*1/1

3P3 = 6

So, in 6 different ways can the three students form a set of class officers.

You might be interested in
plzzz finish 4, 5, 6, 9, 10, 11, 12, 14, and 15 you dont have to answer all but atleast anwer like 2 or 3 \( i scratched out the
nika2105 [10]

Answer:

4. -4

5. -2

6. -3

Step-by-step explanation:

4. -12 = 5r + 8

Subtract 8 from both sides;

-20 = 5r

Divide both sides by 5;

-4 = r OR r = -4

5. -6p - 3 = 9

Add 3 to both sides;

-6p = 12

Divide both sides by -6

p = -2

6. -14 = 4x - 2

Add 2 to both sides;

-12 = 4x

Divide both sides by 4;

-3 = x OR x = -3

8 0
3 years ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
At Pizza Pi, 24% of the pizzas made last week had extra cheese. If 12 pizzas had extra cheese, how many pizzas in all were made
myrzilka [38]

Answer: 50

Step-by-step explanation:

Let the number of pizza made last week be represented by y.

From the question, we can form it into:

24% of y = 12

24/100 × y = 12

0.24 × y = 12

0.24y = 12

y = 12/0.24

y = 50

50 pizza were made last week.

6 0
3 years ago
While playing baseball, sofia takes note of the extreme vectors for which she bats. what is the angle between her two extreme ba
k0ka [10]

The angle between the two extreme vectors of Sofia bats is 74.60 degrees.

In this question,

The angle between two vectors will be deferred by a single point, which is called as the shortest angle at which we have to turn around one of the vectors to the position of co-directional with another vector.

The extreme vectors of Sofia bats are  \vec u = < -8, 12 > and \vec v = < -8, 12 >

The angle between the vectors is

\theta = cos^{-1} \frac{\vec u.\vec v}{||\vec u|| ||\vec v||}

The dot product is calculated as

\vec u. \vec v = (-8)(13)+(12)(15)

⇒ -104+180

⇒ 76

The magnitude can be calculated as

||\vec u|| = \sqrt{(-8 )^{2} +(12)^{2} }

⇒ \sqrt{64+144}

⇒ \sqrt{208}

||\vec v|| = \sqrt{(13 )^{2} +(15)^{2} }

⇒ \sqrt{169+225}

⇒ \sqrt{394}

Thus the angle between the vectors is

\theta = cos^{-1} \frac{76}{(\sqrt{208} )(\sqrt{394} )}

⇒ \theta = cos^{-1} \frac{76}{\sqrt{81952} }

⇒ \theta = cos^{-1} \frac{76}{286.27 }

⇒ \theta = cos^{-1} (0.2654)

⇒ \theta=74.60

Hence we can conclude that the angle between the two extreme vectors of Sofia bats is 74.60 degrees.

Learn more about angle between two vectors here

brainly.com/question/19726452

#SPJ4

5 0
1 year ago
If you were to take a cross section of a right circular cone parallel to its base, what shape would you get?
Leya [2.2K]

The cross section of a right circular cone parallel to its base is a circle.

<h3>What is a three dimensional shape?</h3>

A three dimensional shape is a shape that has length, width and height. Examples of three dimensional shapes are<em> cone, cylinder, prism and pyramid.</em>

A two dimensional shape is a shape that have both length and width. Examples of two dimensional shape are <em>circle, rectangle, square</em>.

A cone is a three-dimensional solid geometric shape having a circular base and a pointed edge at the top

The cross section of a right circular cone parallel to its base is a circle.

Find out more on three dimensional shape at: brainly.com/question/6636176

#SPJ1

3 0
2 years ago
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