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Ostrovityanka [42]
3 years ago
13

This is flipping a figure over the axis of symmrtry

Mathematics
1 answer:
fgiga [73]3 years ago
4 0

Answer:

Step-by-step explanation:

FSDGGHJKL

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Some integers are irrational numbers true or false please explain
Agata [3.3K]
False, all integers are rational because they can be expressed as a fraction. Like -4 is a rational number because it can be -4/1. All integers are rational. 
4 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
The classroom had 35 glue sticks. If the ratio of glue sticks to glue bottles was 5 : 2, how many glue bottles did the classroom
Marat540 [252]

Answer:

14 glue bottles.

Step-by-step explanation:

Let's use a ratio:

sticks : bottles

  5     :     2

  35   :    14

There are 14 glue bottles in the classroom.

7 0
3 years ago
Lol please help meeee
jeyben [28]

Answer:

4 . The answer is no .

5 . x=1

6. unlimited answers

7. There's no answer to this question .

Step-by-step explanation:

___________________

4. solution :

-20(2-4) = 2((5×-4) -4) =

-40 = -48 × impossible

___________________

5. solution :

-3+4x+12x+24 = 28x +12-3

-3+24-12+3=28x-12x-4x

27-15=12 = 2x - 16x =12x

12 = 12x

x =1

__________________

6. solution :

24-3x+9-6 = -8x+20+5x+7

8x-5x-3x = -24-9+6+20+7

0=0

x can be every number you think because they are always equal to each other .

examination :

if you consider x as 1 :

24-3+9-6=-8+20+5+7

24=24

or if you consider x as 2 :

24-6+9-6 = -16+20+10+7

21 = 21

__________________

7 . solution :

3(x-2) = 3x+4

3x-6 = 3x+4

3x-3x = 10

0 = 10

if you consider x as 1 :

3-6 = 3+4

-3 = 7 × impossible .

4 0
3 years ago
Y+1=2(x-4) graph the equation
professor190 [17]

M a t h w a y will help you my friend!

I was struggling with math and using it got me get back on track :)

7 0
3 years ago
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