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Triss [41]
3 years ago
11

I NEED SERIOUS HELP!!! Find the volume of the rectangular prism The volume is __cm. Cubed

Mathematics
1 answer:
GuDViN [60]3 years ago
7 0

Answer: 88cm^2

Step-by-step explanation:

To find the answer of a rectangular prism, use this formula:

A=2(wl+hl+hw)

For your prism, h = 4, l = 6, and w = 2.

A = 2(2*6+4*6+4*2)

A=2(12+24+8)

Area is equal to 88 cm squared.

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Vera_Pavlovna [14]
Here this is the answer

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3 years ago
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Select the correct answer.<br> Which statement is correct with respect to f(x) = -3|x − 1| + 12?
professor190 [17]

Answer:

Opt. D.

Step-by-step explanation:

To solve this problem we need to focus our attention in the abs(x-1) function,

If x>1, then abs|x-1|= x-1, if x<1 then abs|x-1|= 1-x. And in the two intervals, the function opens upwards.

But our function has -3 multiplying abs|x-1|, This means that our function opens downward.

The vertex point can be found when x=1, since abs(x-1)=0. this gives f(1)=12

5 0
4 years ago
Factor the linear expression 15x-10 using the greatest common factor of the terms
Evgesh-ka [11]

Answer:

The answer would be A (3x+2).

8 0
3 years ago
The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?
bearhunter [10]

Answer:

The student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

P = 2l + 2w

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are \sqrt{50a^3b^2}  and  \sqrt{200a^3}\:\:.

Here is the student's solution:

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

                                 =30ab\sqrt{2a}          

The student made an error in calculating 30ab\sqrt{2a}+20a\sqrt{2a} , because 30ab\sqrt{2a}+20a\sqrt{2a} are not like terms.

Hence, 30ab\sqrt{2a}+20a\sqrt{2a} can not be simplified to 30ab\sqrt{2a}

Therefore, the student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

<u></u>

<u>Here is the correct Solution:</u>

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

7 0
3 years ago
Read 2 more answers
If a vector's magnitude is 36 units right and 33 units up, what's the approximate magnitude of a vector that's one-third the len
omeli [17]

Answer:

The correct option is B. 16.3

Step-by-step explanation:

We are given a vector with components

V = 36x +33y

To solve this problem, we find its magnitude

|V| = SQRT (36^2 + 33^2)

|V| = SQRT (2385)

|V| = 48.836

To find the magnitude of the new vector we divide by three the previous quantity

|V2| = 48.836/3 = 16.278

5 0
3 years ago
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