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egoroff_w [7]
2 years ago
14

Solve the equation for x

Mathematics
2 answers:
WARRIOR [948]2 years ago
6 0

Answer:

x = 5

Step-by-step explanation:

2

--- x - 9 = -7              add 9 both sides

 5

2

--- x - 9 + 9 = -7 + 9      

 5

2

--- x = 2             multiply both sides by 5

 5

    2

5 * --- x = 2 * 5

     5

2x = 10

x = 10 / 2

x = 5

Rasek [7]2 years ago
5 0

Answer:

the answer is 5

Step-by-step explanation:

2x/5 - 9 = -7

2x/5      = -7 + 9

2x/5      = 2

2x         = 2 * 5

2x         = 10

x            = 10/2

x            = 5

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Answer:

Step-by-step explanation:

Since we have an amount in the future of 750, we are going to use Future value formula; FV = PV (1+r)^t

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t = ?

Next, plug in the numbers into the formula;

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divide both sides by 500;

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0.4054651 = 0.0246926 t

Divide both sides by 0.0246926 to solve for t;

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Find the answer to (6!) in math
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Step-by-step explanation:

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diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

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3 years ago
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