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aleksley [76]
2 years ago
12

Please help me answer this mathematics question

Mathematics
1 answer:
Sphinxa [80]2 years ago
6 0

Answer:

x = 172.75

Hope this help!!!

Have a good day♡

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There is a total of $39.55. There are 3 times as many dimes as nickels, how many of each coin type was collected ?
katovenus [111]

Number of dimes collected is 339 and number of nickels collected is 113

<em><u>Solution:</u></em>

Given that There is a total of $39.55

There are 3 times as many dimes as nickels

To find: Number of dimes and nickels collected

Let "d" be the number of dimes collected

Let "n" be the number of nickels collected

We know that,

1 dime = $ 0.10

1 nickel = $ 0.05

From given information,

There are 3 times as many dimes as nickels

So, we get

Number of dimes = 3(number of nickels)

d = 3n

Given that there is total of $ 39.55

number of dimes collected x value of 1 dime + number of nickels collected x value of 1 nickel =  $ 39.55

3n \times 0.10 + n \times 0.05 = 39.55\\\\0.3n + 0.05n = 39.55\\\\0.35n = 39.55\\\\n = \frac{39.55}{0.35}\\\\n = 113

Substitute n = 113 in d = 3n

d = 3(113) = 339

<em><u>Summarizing the results:</u></em>

number of dimes collected = 339

number of nickels collected = 113

4 0
3 years ago
Soo uhh ye I need help-
maxonik [38]
Remember PEMDAS.

P=parenthesis
E=exponents
M=multiplication
D=division
A=addition
S=subtraction
7 0
3 years ago
Maria uses 2 centimeters of tape for every present she wraps. Write an equation that shows the relationship between the number o
Marizza181 [45]

Answer:

y = 2x

Step-by-step explanation:

Maria uses 2 centimeters of tape for each present she wraps, and we want a equation that shows the relationship between the number of presents x and the tape used y. To do this, we can establish a rule of three with the information given:

1 present wrapped -> 2 centimeters of tape

x presents wrapped -> y centimeters of tape

1/x = 2/y

x = y/2 -> y = 2x

From this relation, we know that to make x presents, Maria will use 2x centimeters of tape.

6 0
3 years ago
The sum of 3 consecutive odd integers is 7 less than 4 times the largest number. Find all 3 #’s plz show work
oksian1 [2.3K]
-3, -1, and 1
-3 - 1 + 1 = -3
4*1= 4
4 - 7 = -3
3 0
3 years ago
Read 2 more answers
Find the sum of the first 30 terms of the sequence. a_(n)=4n+1
oksian1 [2.3K]
We know that
a(n)=4n+1
To find the sum of the first n<span> terms of an arithmetic series
use the formula
</span><span><span>Sn</span>=<span>n(<span>a1</span> + <span>an</span>)/2
</span></span>a1--------------> is the first term
an--------------> is the last term
n--------------- > <span>is the number of terms
</span>we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890

the answer is 1890


7 0
3 years ago
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