Answer:
1) The value of c is given by

2) The value of k is given by

Step-by-step explanation:
Given that function g is defined by
, where c is a constant.
To find c:
Also given that value of g(x) at x=0.5 is equal to -1
ie., 
At x=0.5






Therefore 
2) Given that function h is defined by
, where k is a constant.
To find k:
Also given that value of h(x) at x=20 is equal to 65
ie., 
At x=20



Therefore 
Answer:
$904,510.28
Step-by-step explanation:
If we assume the withdrawals are at the beginning of the month, we can use the annuity-due formula.
P = A(1 +r/n)(1 -(1 +r/n)^(-nt))/(r/n)
where r is the APR, n is the number of times interest is compounded per year (12), A is the amount withdrawn, and t is the number of years.
Filling in your values, we have ...
P = $4000(1 +.034/12)(1 -(1 +.034/12)^(-12·30))/(.034/12)
P = $904,510.28
You need to have $904,510.28 in your account when you begin withdrawals.
Answer:
7. f₍ₓ₋₂₎ - 7
9. f₍₋ₓ₎ + 3
11. Vertical stretch by the factor of 12 and translated 2 units up
Step-by-step explanation:
This is my best guess and wish it is good. Otherwise report it.
C.
-2(4-1)
Distributing: (-8 +2) = -6