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3 years ago

A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.

Mathematics

2 answers:

Neporo4naja [7]3 years ago

8 0

Answer:

7.5mph

Step-by-step explanation:

Speed = Distance / Time

Speed = 15 ÷ 2

Speed = 7.5 mph

Sauron [17]3 years ago

5 0

The formula for speed is s = d ÷ t, or speed equals distance divided by time.

Divide the cyclist's distance by his time.

15 ÷ 2 = 7.5

<h2>Answer:</h2>

The cyclist's speed is 7.5 mph.

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The function f(x) = –x2 + 20x – 75 models the profit from one customer, in dollars, a shop makes for printing photos, where x is

trasher [3.6K]

The function is graphed as shown below

Part A:

We use the formula $- \frac{b}{2a}$ to find the vertex of the function. A quadratic function of the form of $a x^{2} +bx+c$ and equating this form to the given function $- x^{2} +20x-75$ , we have
$b=20$ and $a=-1$ .

Substituting $a$ and $b$ into the vertex formula, we have
$x=- \frac{20}{2(-1)}=10$ , as shown in the graph

This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos

Part B:

We can find solution to this equation by factorising

$- x^{2} +20x-75=0$
$-( x^{2} -20x+75)=0$
$x^{2} -20x+75=0$
$(x-5)(x-15)=0$
$x=5$ and $x=15$ , as shown in the graph

The two values means that the company makes no profit when they either produce 5 or 15 photos

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3 years ago

Given f(x) = x⁴- 3x³ + 9x²- 17x + 42 and g(x) = -x² - x - 6, where g(x) cant equal 0, find (f/g)(x)

12345 [234]

Step-by-step explanation:

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3 years ago

What is the relationship between the 3's in the number 9,338?

Serhud [2]

The 3 in the hundreds place (value of 300) has a value that is 10x the 3 in the tens (value of 30).

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2 years ago

Read 2 more answers

Helppp please if anyone know

zmey [24]

81 - 35+30 (55) = 26 therefore 26cm is ur final answer

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3 years ago

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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars

Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

Every x has only one value of y

x appears once in ordered pairs

Examples:

The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)

The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)

The domain is the set of values of x

The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

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2 years ago