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4 years ago

Can someone assist me on this

Mathematics

2 answers:

Savatey [412]4 years ago

8 0

Answer:

The perimeter of the triangle would be 21.2. The area would be 18 ft^2

Step-by-step explanation:

Hope this helps :)

Attached is the work I did to get the answers

Aleks04 [339]4 years ago

5 0

The perimeter would be 21.2 and 18 ^2 feat would be the area correct me if I’m wrong

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solniwko [45]

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3 years ago

Determine the value of the variables when simplifying and evaluating the expression (302)0 .

Dvinal [7]

Answer:

M=0

(30^2)^0 = 1

Step-by-step explanation:

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4 years ago

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hoa [83]

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Step-by-step explanation:

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3 years ago

Rectangle JKLM:J(-3, 8), K(-3,-1), L(4, -1),

Maslowich

Answer:

The perimeter of the Rectangle JKLM is 32 unit.

Step-by-step explanation:

Consider the provided coordinates.

Rectangle JKLM: J(-3, 8), K(-3,-1), L(4, -1), M(4,8)

First plot the points as shown in figure:

The required figure is shown below:

Now find the distance between JK by using the distance formula.

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$d=\sqrt{\left(-3-\left(-3\right)\right)^2+\left(-1-8\right)^2}=9$

Therefore, the length of JK is 9 unit.

Now find the length of the side JM

$d=\sqrt{\left(4-\left(-3\right)\right)^2+\left(8-8\right)^2}=7$

Therefore, the length of JM is 7 unit.

The perimeter of rectangle is: $P=2(l+b)$

Therefore,

$P=2(7+9)$

$P=2(16)$

$P=32$

Hence, the perimeter of the Rectangle JKLM is 32 unit.

4 0

4 years ago

Simplify by rationalizing the denominator. 15√2 / √270

ladessa [460]

$\frac{ \sqrt{15} }{3}$ ✅

Step-by-step explanation:

$\frac{15 \sqrt{2} }{ \sqrt{270} } \\ \\ = \frac{15 \sqrt{2} }{ \sqrt{270} } \times \frac{ \sqrt{270} }{ \sqrt{270} } \\ \\= \frac{15 \sqrt{2} \times \sqrt{270} }{270} \\\\ (∵ \sqrt{a} \times \sqrt{a} = a) \\\\ = \frac{15 \sqrt{540} }{270} \\ \\= \frac{ \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 5} }{18} \\ \\ = \frac{ \sqrt{ {2}^{2} \times {3}^{2} \times 15 } }{18} \\ = \frac{2 \times 3 \sqrt{15} }{18} \\ \\ = \frac{6 \sqrt{15} }{18} \\ \\ = \frac{ \sqrt{15} }{3}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}$

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3 years ago

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Can someone assist me on this​

Can someone assist me on this