A hot air balloon is released into the air. During its straight ascent, the angle of elevation was 15° and, 3 minutes later, the
angle of elevation increased 20°. How fast is the balloon traveling, in km/h, if the angle measurements were taken 300m away from the launch site?
1 answer:
Answer:
The speed of balloon is 0.16 m/s.
Step-by-step explanation:
BC = 300 m
AD = x
AB = y
time, t = 3 min = 3 x 60 = 180 s
By the triangle, ADC,

By the triangle, BDC

So, y = 109.2 - 80.4 = 28.8 m
Speed of balloon = 28.8/180 = 0.16 m/s
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