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butalik [34]
3 years ago
10

A 4000 kg truck is parked on a 7.0° slope. How big is the friction force on the truck?

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

4777.28 N

Step-by-step explanation:

The gravitational force down the slope is given by the formula;

(mass *g * sin θ )  

where;

θ is the angle of inclination of the slope

g is the gravitational pull

We plug in the given values into the above expression;

(4,000 x 9.8 x sin 7) = 4777.28 N.  

The frictional force must equal to 4777.28 N (pointing up the slope).

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The greatest integer less than or equal to the given number; it is expressed: [[x]]. These are sometimes called step functions.
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Answer:

I think its, 5

Step-by-step explanation:

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:D

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4 years ago
Plz help ill give you brainlist
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6 0
3 years ago
Match the statements in the table with the words/phrases contained in the word bank<br> Word Bank:
kykrilka [37]

Answer:

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6 0
3 years ago
A new health drink has ​% of the recommended daily allowance​ (RDA) for a certain vitamin. The RDA for this vitamin is mg. How m
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Step-by-step explanation:

6 0
3 years ago
Math question down below
mezya [45]

y=1 is the answer, there is no slope, so the formula y=mx+b turns into y=b, since 1 is the intercept 1 is b.

6 0
3 years ago
Read 2 more answers
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