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romanna [79]
3 years ago
15

R(r1+r2) = r1r2, For r2

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
R(r_1+r_2)=r_1r_2\\
Rr_1+Rr_2=r_1r_2\\
Rr_2-r_1r_2=-Rr_1\\
r_2(R-r_1)=-Rr_1\\
r_2=-\dfrac{Rr_1}{R-r_1}

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a line passes through the point (-3,-5) and has a slope of 5 write an equation in point slope form for this line
Tanzania [10]

Answer:

y=5x+10

Step-by-step explanation:

1) Plug numbers into slope formula to find b.

y=mx+b

-5=5(-3)+b

2) Simplify to find b.

-5=-15+b

10=b

3) Check work.

-5=-15+10

This statement is true.

4) Write equation.

y=5x+10

4 0
2 years ago
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3 years ago
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3 years ago
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Sarah has 273 feet of wire to make bead necklaces. If each necklace requires 1 2/3 feet of wire, how many necklaces can she make
o-na [289]

Oh boy, here we go again

First we must convert  1 2/3 to an improper fraction.  By doing this, we get 5/3  (3/3 + 2/3)

So now we have 273 /  5/3

To divide this easier we can do something that when I learned it was called (keep, change, flip)  which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction

This now turns into:  273/1 * 3/5

Combine 273 and 3/5

273⋅3/5

Multiply 273

by 3

819/5

is your answer

5 0
3 years ago
If a 2-kg block compresses a spring 800mm from its relaxed state, how much potential energy does the block have due to the sprin
Tju [1.3M]

Answer:

8 Joule

Step-by-step explanation:

Mass of block = 2 kg

Displacement = x = 800 mm = 0.8 m

Spring constant = k = 25 N/m

Potential Energy of a spring

Work done = Difference in Potential Energy

Work Done = Δ P.E.

\Rightarrow \Delta\ P.E.=\frac{1}{2}kx^2

⇒P.E. = 0.5×25×0.8²

⇒P.E. = 8 Nm = 8 Joule

Here already the spring constant and displacement is given so the mass will not be used while calculating the potential energy.

5 0
3 years ago
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