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3 years ago

Help me solve this problem

Mathematics

2 answers:

kakasveta [241]3 years ago

6 0

Answer:

Step-by-step explanation:

1.Tan = opp/adj

Tan 45=x/8

Cross multiply

Tan 45 x 8 = x

1 x 8=x

X =8

2.sin=opp/hyp

Sin 45=8/y

Cross multiply

Sin45 x y =8

Divine both sides by sin45

Y = 8/sin 45

Y=8 ÷√2/2

Y=8 x 2/√2

Y=16/√2

Rationalise

Y= 16/√2 x√2/√2

Y=16√2/2

16 divided by 2 is 8

Y=8√2

Degger [83]3 years ago

6 0

Answer: x = 8 y = 8√2

Step-by-step explanation: If both angles are the same, 45° the sides are the same, so x = 8.

To find the hypotenuse, y, use the Pythagorean Theorem: a² + b² = c²

(In this question, c is y, and the x sides are a & b)

8² + 8² = y² Here you can add the squares 66 + 64 = 128 and calculate the square root of 128 OR

(8²)(2) = y² √(8²)(2) = √y²

8√2 = y

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Maxim has been offered positions by two car companies. The first company pays a salary of $8000 plus a commission of $900 for ea

Kaylis [27]

Answer:

16 cars.

Step-by-step explanation:

Let x represent number of sold cars.

We have been that 1st company pays a salary of $8000 plus a commission of $900 for each car sold. We can represent this information in an expression as:

$900x+8000$

We are also told that second company pays a salary of $14400 plus a commission of $500 for each car sold. We can represent this information in an expression as:

$500x+14,400$

To find the number of cars sold, which will make the total pay the same, we will equate both expressions and solve for x as:

$900x+8000=500x+14,400$

$900x-500x+8000=500x-500x+14,400$

$400x+8000-8000=14,400-8000$

$400x=6,400$

$\frac{400x}{400}=\frac{6,400}{400}$

$x=16$

Therefore, 16 cars would need to be sold to make the total pay the same.

3 0

4 years ago

Tom fed his chickens with grains on Sun. The chickens ate a 1/4 of what was given to them that day. On Mon, the chickens ate a 1

SVETLANKA909090 [29]

Answer:

1/2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How many bit strings of length 10 do not contain the substring 00? In other words, how many strings of length 10, consisting onl

vova2212 [387]

Answer:

144

Step-by-step explanation:

For a bitstring of length n, there are Fibonacci(n+2) strings containing no two consecutive zeros. This can be seen by constructing the strings starting with n=1.

1-bit strings: 1, 0 -- 2 strings not containing consecutive 0s

2-bit strings: 11, 10, 01 -- 3 strings not containing consecutive 0s

Note that we have added 1 to all the 1-bit strings, and added 0 only to the string ending in 1.

3-bit strings: 111, 110, 101, 011, 010 -- 5 strings not containing consecutive 0s

Note that these 5 strings consist of all (3) of the 2-bit strings with 1 appended, and all (1) of the 2-bit strings ending in 1 with 0 appended. The number that now end in 0 is the number previously ending in 1.

If (x, y) represents the numbers of n-bit strings ending in (0, 1), then the number of (n+1)-bit strings ending in (0, 1) is (y, x+y). That is, the recursive relation is ...

$(x_1,y_1)=(1,1)\\(x_n,y_n)=(y_{n-1},\,x_{n-1}+y_{n-1})\\b_n=x_n+y_n\quad\text{number of n-bit strings without consecutive 0s}$

For n=1 to n=10, these pairs are ...

(1, 1), (1, 2), (2, 3), (3, 5), (5, 8), (8, 13), (13, 21), (21, 34), (34, 55), (55, 89)

The sequence of b[n] values is ...

2, 3, 5, 8, 13, 21, 34, 55, 89, 144

which are the n=3 to n=12 numbers from the Fibonacci sequence.

That is, there will be Fibonacci(12) = 144 10-bit strings with no consecutive 0s.

5 0

3 years ago

I lowkey need help on number five like I don’t get it . Am I doing something wrong cause I feel like I am ? And which equation w

Tpy6a [65]

43,802 round to tha nearest thounsand

5 0

3 years ago

The mean incubation time for a type of fertilized egg kept at 100.2100.2âÂ°f is 2323 days. suppose that the incubation times are

zlopas [31]

To solve this problem, what we have to do is to calculate for the z scores of each condition then find the probability using the standard normal probability tables for z.

The formula for z score is:

z = (x – u) / s

where,

x = sample value

u = sample mean = 23 days

s = standard deviation = 1 day

A. P when x < 21 days

z = (21 – 23) / 1

z = -2

Using the table,

P = 0.0228

Therefore there is a 2.28% probability that the hatching period is less than 21 days.

B. P when 23 ≥ x ≥ 22

P (z=-1) = 0.1587

z (x=23) = (23 – 23) / 1 = 0

P (z=0) = 0.5

P = 0.5 - 0.1587 = 0.3413

Therefore there is a 34.13% probability that the hatching period is between 22 and 23 days.

C. P when x > 25

z = (25 – 23) / 1

z = 2

P = 0.9772

This is not yet the answer since this probability refers to the left of z. Therefore the correct probability is:

P true = 1 – 0.9772

P true = 0.0228

<span>Therefore there is a 2.28% probability that the hatching period is more than 25 days.</span>

8 0

3 years ago