I dont get what to do
2 answers:
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The range of y=e^x+1 is y>1.
the numbers are 3 and 18
let the first number be n then the second number = 6n and the sum
sum = n + 6n = 21 thus
7n = 21
divide both sides of the equation by 7
n = = 3
the numbers are 3 and 6 × 3 = 18 → (3 + 18 = 21)