I dont get what to do
2 answers:
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The tangent to at the point (0, 5) has a slope equal to the derivative evaluated at
.
This tangent passes through the point (0, 5), so its equation is
The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is
There is a property called "Quotient of powers property", which states that:
Where "a" is the common base and "m" and "n" are exponents.
For this case, you have:
Then, in order to find the quotient, you must apply the Quotient of powers property. You need to write the common base (in this case is 3) and then subtract the exponents.
So, you get that the quotient is:
Y = 4x - 3
y = mx + b
m = 4
b = -3
y intercept = (0,3)
(x,y) = (0,3)
(x,y) = (1,1) - substitute in ori equation
y = mx + b
m = 4
b = -3
y intercept = (0,3)
(x,y) = (0,3)
(x,y) = (1,1) - substitute in ori equation