Three angles are in the ratio 2 : 3 : 5 The smallest angle is 50 degrees Work out the sizes of the other two angles

1 answer:

5 0

Since the smallest angle is 50 degrees, then divide 50 by 2 (because of the ratio) and you get 25. Now you can multiply 25 by 3 and 25 by 5 to get the remaining angles which would be 75 degrees and 125 degrees.

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Someone please help me!

andrezito [222]

The standard form of a parabole is: (y-k) = a(x-h)², Where (h , k) are the coordinates of the vertex
In the example Vertex (3,1) ,
so (y-1) = a(x-3)². (a)
Now let's calculate a. The y-intercept coordinates(0 , 10), Replace in (a) x by 0 & y by 10:
(10-1) = a(0 - 3)²
9 = 9a and a=1
<u />The equation becomes : y-1 = (x-3)², Expand (y-1) = x²-6x+9
<u />and finally y = x² - 6x +10 (ANSWER C)

6 0

3 years ago

What is the binomial expansion of (x 2y)7? 2x7 14x6y 42x5y2 70x4y3 70x3y4 42x2y5 14xy6 2y7 x7 14x6y 42x5y2 70x4y3 70x3y4 42x2y5

AysviL [449]

You can take x = a, 2y = b and then can apply the binomial theorem.

The expansion of given expression is given by:

Option D: $x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7$ is

<h3>What is binomial theorem?</h3>

It provides algebraic expansion of exponentiated(integer) binomial.

According to binomial theorem,

$(a+b)^n = \sum_{i=0}^n ^nC_i a^ib^{n-i}$

<h3>How to use binomial theorem for given expression?</h3>

Taking a = x, and b =2y, we have n = 7, thus:

$(x+2y)^7 = \: ^7C_0x^0(2y)^7 + \: ^7C_1x^1(2y)^6 + \: ^7C_2x^2(2y)^5 + \: ^7C_3x^3(2y)^4 + \:^7C_4x^4(2y)^3 + \:^7C_5x^5(2y)^2 + \:^7C_6x^6y^1 + \: ^7C_0x^7y^0\\\\
(x+2y)^7 = 128y^7 + 448xy^6 + 672x^2y^5 + 560x^3y^4 + 280x^4y^3 + 84x^5y^2 + 14x^6y + x^7\\\\
(x+2y)^7 = x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7$