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2 years ago

Solve a = d+c/b for d

Mathematics

1 answer:

sesenic [268]2 years ago

6 0

Answer: d = a - c/b

Plz mark brainliest:)

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12/15 * 5/6

nydimaria [60]

La multiplicación de las fracciones es 2/3

Para multiplicar las dos fracciones tenemos que multiplicar en línea: numerador por numerador y denominador por denominador.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\sf \rightarrow \dfrac{12}{15} \times \dfrac{5}{6} }$

Resolvamos:

$\: \: \: {\sf \rightarrow\dfrac{12}{15}\times \dfrac{5}{6}=\dfrac{12 \times 5}{15 \times 6}=\dfrac{60}{90} =\dfrac{2}{3} }$

Por lo tanto, la multiplicación de las fracciones es 2/3

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2 years ago

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Mumz [18]

Answer:

the result is : 14x + 27

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3 years ago

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Lim as x->ln2 of ((e^3x)-8)/((e^2x)-4)

andriy [413]

X ⇒ ln (2)

e^3 x - 8/e^2 x - 4

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2 years ago

Which graphs show continuous data?<br><br> Select each correct answer.

love history [14]

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Due to the fact that it is starting from 0 and moving in a steady pattern

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2 years ago

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the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.

suter [353]

Answer:

The width of the photo is $4w^2+6w+4$ .

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

$6w^2+8$

The photo is covered by a frame border and the width of the border is

$w^2-3w+2$

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

$\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})$

$\text{Width of the photo}=6w^2+8-2(w^2-3w+2)$

$\text{Width of the photo}=6w^2+8-2w^2+6w-4$

$\text{Width of the photo}=4w^2+6w+4$

Therefore the width of the photo is $4w^2+6w+4$ .

4 0

2 years ago