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3 years ago

If mAngleDAC = 25°, what is mAngleDAB in degrees?

Mathematics

1 answer:

Alla [95]3 years ago

6 0

I will need you to insert a picture of the angles so I can tell you their measure

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Ashley made 2 out of 4 attempted shots. Does the 2 shots she made represent the whole or the part of our proportion?

emmainna [20.7K]

Part because the whole proportion would be 4/4 and 2/4 is part of it

5 0

3 years ago

Kerry read 2/3 of her chemistry book containing 420 pages. David read 3/4 of the same. Who read more pages and by how many pages

Alika [10]

Answer:

Kerry = 2/3 * 420 = 280

David = 3/4 * 420 = 315

David read more pages compared to Kerry.

3 0

3 years ago

Two equations are shown.

Korvikt [17]

Answer:

x=15 and y=18

Step-by-step explanation:

1: 2/3x- 4=6 2/3x=10 x=15

1: x=15

2: 2/3y=12

y=18

5 0

3 years ago

10/14 a/10.5 <br><br> solve for A with explanation

photoshop1234 [79]

Answer:

$a = 7.5$

Step-by-step explanation:

Given

$\frac{10}{14} = \frac{a}{10.5}$

Required

The value of a

Cross multiply

$a * 14 =10 * 10.5$

Make a the subject

$a = \frac{10 * 10.5}{14}$

$a = \frac{105}{14}$

$a = 7.5$

5 0

3 years ago

Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and

cluponka [151]

Answer:

Thus, the expected value of points for Derek and Mia are $\dfrac{-1}{9}$ and $\dfrac{1}{9}$ respectively.

Step-by-step explanation:

Number of green marbles = 2 and Number of Yellow marbles = 1

Then, total number of marbles = 2+1 = 3

A person selects two marbles one after another after replacing them.

So, the probabilities of selecting different combinations of colors are,

$1.\ P(GG)=P(G)\times P(G)\\\\P(GG)=\dfrac{2}{3}\times \dfrac{2}{3}\\\\P(GG)=\dfrac{4}{9}$

$2.\ P(GY)=P(G)\times P(Y)\\\\P(GY)=\dfrac{2}{3}\times \dfrac{1}{3}\\\\P(GY)=\dfrac{2}{9}$

$3.\ P(YG)=P(Y)\times P(G)\\\\P(YG)=\dfrac{1}{3}\times \dfrac{2}{3}\\\\P(YG)=\dfrac{2}{9}$

$4.\ P(YY)=P(Y)\times P(Y)\\\\P(YY)=\dfrac{1}{3}\times \dfrac{1}{3}\\\\P(YY)=\dfrac{1}{9}$

Now, we have that,

If two marbles are of same color, then Mia gains 1 point and Derek loses 1 point.

If two marbles are of different color, then Derek gains 1 point and Mia loses 1 point.

<h3>Also, the expected value of a random variable X is $E(X)=\sum_{i=1}^{n} x_i\times P(x_i)$ .</h3>

Then, the expected value of points for Derek is,

$E(D)= (-1)\times \dfrac{4}{9}+1\times \dfrac{2}{9}+1\times \dfrac{2}{9}+(-1)\times \dfrac{1}{9}\\\\E(D)= \dfrac{-5}{9}+\dfrac{4}{9}\\\\E(D)=\dfrac{-1}{9}$

And the expected value of points for Mia is,

$E(M)= 1\times \dfrac{4}{9}+(-1)\times \dfrac{2}{9}+(-1)\times \dfrac{2}{9}+1\times \dfrac{1}{9}\\\\E(M)= \dfrac{5}{9}-\dfrac{4}{9}\\\\E(M)=\dfrac{1}{9}$ .

Thus, the expected value of points for Derek and Mia are $\dfrac{-1}{9}$ and $\dfrac{1}{9}$ respectively.

8 0

3 years ago

Read 2 more answers