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artcher [175]
3 years ago
15

A pair of parallel lines is cut by a transversal which group of angles measures 43?

Mathematics
1 answer:
Kaylis [27]3 years ago
3 0

C) is your answer because 180-137=43 and angle 1,3,5,7 are transversal to 137 degree angles

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Please help out guys.
Kobotan [32]

Answer:

39

Step-by-step explanation:

-\left(\left(-1\right)^2-4\right)^3-4\left(-3\right)

=-\left(-3\right)^3-4\left(-3\right)

=-\left(-27\right)-4\left(-3\right)

=-\left(-27\right)-\left(-12\right)

=39

7 0
3 years ago
Two containers, X and Y, are each filled by an ideal gas at the same temperature. The volume of Y is half the volume of X. The n
-Dominant- [34]

Answer:

The answer to the question is

The ratio of the two gas pressures   \frac{P_{x} }{P_{y} } , that is Px to Py = 1/6

Step-by-step explanation:

Let the gases Volumes be V₁ and V₂

Where volume of X = V₁ and

volume of Y = V₂

The volume of Y is half the volume of X

∴ V₂  =  \frac{1}{2} × V₁

Let the number of moles be n₁ and n₂ in X and Y respectively

therefore  n₂ = 3 × n₁

The pressure of the gas in X is Pₓ and the pressure of the gas in Y is  P_{y} then we have

P₁ × V₁  = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂

(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)

but T₁ = T₂

Therefore

(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂.  However  n₂ = 3 × n₁  and V₂  =  \frac{1}{2} × V₁ therefore substituting in the equation we have

(P₁ × V₁)/n₁ = (P₂ ×  \frac{1}{2} × V₁ )/(3 × n₁) from where

P₁ /P₂ =  (\frac{1}{2} × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6

The ratio of \frac{P_{x} }{P_{y} } = 1/6

6 0
4 years ago
A rectangular poster has an area of 26 square feet. It is 4 1/3 feet wide at it's base. What is the height of the poster?
Alexandra [31]

Answer:

6 square feet

Step-by-step explanation:

Area = L * w

26    =  L * 4 1/3

26  =   L * 13/3

L  = 26 divided by 13/3

L = 26 * 3/13  =  6

answer = 6

8 0
3 years ago
Increase 2384598 by 6 million
qaws [65]
2384598 + 6000000 = 8384598
6 0
3 years ago
Read 2 more answers
Please help me no one even bothers to help so plzzzz i BEGGGGGGGGGGG
user100 [1]

Answer:

Here's what I get.

Step-by-step explanation:

When you dilate an object by a scale factor, you multiply its coordinates by the same number.

If the scale factor is 4, the rule is (x, y) ⟶ (4x, 4y)

Your table then becomes

\begin{array}{lcl}\textbf{Vertices of}& \, & \textbf{Vertices of}\\\textbf{VWXY}& \, & \textbf{V'W'X'Y'}\\V(-1 ,1) & \quad & V'(-4, 4)\\W(-1, 2) & \quad & W'(-4, 8)\\X(2, -1) & \quad & X'(8 ,-4)\\Y(2, 2) & \quad & Y'(8, 8)\\\end{array}

The diagram below shows figure VVXY as a green bow-tie and its image V'W'X'Y' in orange.

The scale factor is greater than one, so the dilation is an enlargement.

7 0
3 years ago
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