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fomenos
3 years ago
11

Three security cameras were mounted at the corners of a triangular parking lot. Camera 1 was 106 ft from camera 2, which was 133

ft from camera 3. Cameras 1 and 3 were 151 ft apart. Which camera had to cover the greatest angle?]
A. Camera 3
B. Cannot tell
C. Camera 2
D. Camera 1

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0
Correct Answer: 
Option C. Camera 2

The greatest angle is always opposite to the side measure greater in length. So first we find the greatest side.

The distance between cameras is:

Camera 1 and Camera 2 : 106 feet
Camera 2 and Camera 3 : 133 feet
Camera 1 and Camera 3 : 151 feet

So the largest side of the triangle is the side between camera 1 and camera 3. So the camera opposite to this side will have to cover to greatest angle. The camera opposite to this side is Camera 2. This scenario is also shown in figure below.

Therefore, Camera 2 had to cover the greatest angle. 

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Input in stand form the equation of the given line.
Daniel [21]

Answer:

  3x +8y = -17

Step-by-step explanation:

The point-slope equation is a good place to start.

  y -k = m(x -h) . . . . . equation through (h, k) with slope m

Filling in your numbers gives ...

  y +4 = -3/8(x -5)

Multiplying by 8, we get

  8y + 32 = -3x + 15

Adding 3x-32 puts this in standard form.

  3x + 8y = -17

_____

Standard form is ...

  ax +by = c

where a, b, c are mutually-prime integers and the leading coefficient is positive. (If a=0, the leading coefficient is b.)

8 0
3 years ago
37.5 to the nearest degree
frutty [35]

Answer:

38 degrees

Step-by-step explanation:

if it is half a tenth or more, it gets rounded up to the next degree

5 0
3 years ago
Read 2 more answers
4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis
Jet001 [13]

Answer:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

X \sim Unif (a= 20, b =50)

The cumulative distribution function is given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

The expected value is given by:

E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35

And we want to find the following probability:

P(35-2 < X 35+2) = P(33< X< 37)

And we can find this probability on this way:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

8 0
3 years ago
Jeff must do a book report. He reads 3 pages of his book in 13 minutes. He reads 9 pages of his book in 39 minutes. He reads 15
svlad2 [7]
Do you see a pattern in the given information?
 3 pages in 13 min
 9 pages in 39 min
15 pages in 65 min

the rate of pages per min is constant
3/13 = 9/39 = 15/65

the Question is asking for time.. So the we need the rate as min per page 13/3 so when multiplied by the number of pages it cancels to give minutes.

Units cancel out just like numbers do so you know that the problem is set up correctly.

(351 pages) * ( \frac{13min}{3pages})=1521 .minutes

7 0
3 years ago
What is the volume of the following triangular pyramid?
Readme [11.4K]

Answer:

The volume of the triangular  pyramid

         V = 566.66 in³

Step-by-step explanation:

<u><em>Step(i):-</em></u>

The volume of the triangular  pyramid

            = \frac{1}{3} X base area X height

Base area  = Area of the triangle

             A= \frac{1}{2} X base  X height

 Given the base of the triangle  (b) = 17in

  Given Height of the triangle (h ) =10 in

    A= \frac{1}{2}( 17 ) (10) = 85

The base area of the pyramid ( A) = 85 in²

<u><em>Step(ii):-</em></u>

<u><em>Given the height of the pyramid  (h) = 20in</em></u>

The volume of the triangular  pyramid

            = \frac{1}{3} X base area X height

The volume of the triangular  pyramid

         = = \frac{1}{3}( 85)(20) = 566.66

<u><em>Final answer:-</em></u>

The volume of the triangular  pyramid

         V = 566.66 in³

3 0
3 years ago
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