All categories

3 years ago

What is the geometric mean between 9/16 and 25/36

Mathematics

1 answer:

sergiy2304 [10]3 years ago

6 0

Answer:

5/8

Step-by-step explanation:

Geometric mean is found by multiplying the n number of values and then taking the n-root.

To do this with these numbers, sqrt((9/16)*(25/36)) = (3/4)(5/6) = (1/4)(5/2)= 5/8

I hope this helps! :)

You might be interested in

A rectangular painting canvas has the dimensions of 22 by 23 inches. Find the area, in square inches, of the painting. Use the f

fiasKO [112]

Answer:

506 square inches

Step-by-step explanation:

length=22 inches

breadth=23 inches

area=length *breadth

area=22*23=506 squareinches

4 0

3 years ago

Read 2 more answers

How much chromium-51 will be left after 7 months?

Makovka662 [10]

Answer:

It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

The half-life of chromium 51 is 27.7 days.

After 7 months, chromium 51 will have undergone 7.69 half-lives.

To solve for the ending amount we'll use the formula:

Ending Amount = Beginning Amount / 2^n where 'n' = # of half-lives

We'll say the beginning amount =1

Ending Amount = 1 / 2^7.69

Ending Amount = 0.0048426082

Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

Source: https://www.1728.org/halflife.htm

Step-by-step explanation:

6 0

3 years ago

How do you find the product of (3x+4)^2

Sliva [168]

each number and variable inside the parentheses has an exponent, in this case all of them are 1.

3^2 * x^2 + 4^2

9*x^2+16

final answer:

4 0

3 years ago

Based on a sample of 100 employees a 95% confidence interval is calculated for the mean age of all employees at a large firm. Th

babymother [125]

Answer:

$\= x = 40.85$

$E = 5.85$

$t_c = 2.08$

$t_c = 1.282$

Explanation:

From the question we are told that

The sample size is n = 100

The upper limit of the 95% confidence interval is b = 47.2 years

The lower limit of the 95% confidence interval is a = 34.5 years

Generally the sample mean is mathematically represented as

$\= x = \frac{a + b }{2}$

=> $\= x = \frac{47.2 + 34.5 }{2}$

=> $\= x = 40.85$

Generally the margin of error is mathematically represented as

$E = \frac{b- a }{ 2}$

=> $E = \frac{47.2- 34.5 }{ 2}$

=> $E = 5.85$

Considering question C a

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

The sample size is n = 22

Given that the sample size is not sufficient enough i.e $n < 30$ we will make use of the student t distribution table

Generally the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 22 - 1$

=> $df = 21$

Generally from the student t distribution table the critical value of $\frac{\alpha }{2}$ at a degree of freedom of 21 is

$t_c =t_{\frac{\alpha }{2} , 21 } = 2.08$

Considering question C b

From the question we are told the confidence level is 80% , hence the level of significance is

$\alpha = (100 - 80 ) \%$

=> $\alpha = 0.20$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$t_c =Z_{\frac{\alpha }{2} } = 1.282$

4 0

3 years ago

Enter values to write the function that matches the graph shown.

Bogdan [553]

Answer:

h(x) = (-2x + 4)(3x − 3 )

Step-by-step explanation:

4 0

3 years ago