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Daniel [21]
3 years ago
13

What is the geometric mean between 9/16 and 25/36

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

5/8

Step-by-step explanation:

Geometric mean is found by multiplying the n number of values and then taking the n-root.

To do this with these numbers, sqrt((9/16)*(25/36)) = (3/4)(5/6) = (1/4)(5/2)= 5/8

I hope this helps! :)

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True

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2 years ago
The population of a species of rabbit triples every year. This
jok3333 [9.3K]

Answer:

"4" represents that there are 4 rabbit in the beginning.

Step-by-step explanation:

Given that the population of a species of rabbit triples every year. This

can be modeled by function f\left(x\right)=4\left(3\right)^x and f(5) = 972.

Now we need to find about what does the 4 represent in the given function.

We know that exponential function is given by f\left(x\right)=a\left(b\right)^x. Where "a" represents the initial amount.

we have a=4 in given function f\left(x\right)=4\left(3\right)^x.

So that means "4" represents that there are 4 rabbit in the beginning.

3 0
3 years ago
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
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