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soldi70 [24.7K]
4 years ago
6

The amount of energy it takes to lift a box might be a function of which of the

Mathematics
1 answer:
Doss [256]4 years ago
6 0

Answer:

  A. The weight of the objects inside the box

Step-by-step explanation:

The energy required to lift a box is a function of the weight of it and of the distance it is lifted.

_____

In physics terms, the energy is the product of force and distance. The applicable force when lifting the box is the weight of the box (the box itself and any objects inside).

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What is the solution to the inequality 13 x + 3 < 42 ?
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Answer:

x < -15

Step-by-step explanation:

Here is the solution:

-3x-42 > 3

Add the numbers

-3x > 45

Divide both sides of the inequation by -3 and flip the inequality sign.

x < -15

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3 years ago
Logan can make $50 per pool to clean pools during the summer to earn money. He did, however, need to
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Step-by-step explanation:

y = 50x - 165

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2 years ago
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solmaris [256]

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12

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8 0
3 years ago
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Figure ABCDE has vertices A(−2, 3), B(2, 3), C(5, −2), D(0, −3), and E(−2, −2). Plot the points on your own coordinate grid and
Alina [70]
A) The figure decomposes nicely into 1 rectangle and 2 triangles.

B) AB = 4 units; AE = 5 units.

C) The rectangle whose diagonal is BE has area 4*5 = 20 units^2.
.. The triangle CDE has area (1/2)*7*1 = 7/2 units^2.
.. The triangle BCF has area (1/2)*3*5 = 15/2 units^2.
The total area of the figure is
.. area = rectangle + triangle CDE + triangle BCF
.. = (20 +7/2 +15/2) units^2
.. = 31 units^2

_____
Check:
.. Compare our computed value of area to that listed for poly1 on the left side of the figure.

3 0
4 years ago
A rectangle with an area of 24 square units has length x+1 and width 4x-6. find the value of x.
dimulka [17.4K]
area = length \cdot width \\ \\A = 24 s^2 \\ \\ l=x+1 , \ \ w=4x-6 \\ \\ A=lw\\ \\24 =(x+1)(4x-6)

24 =4x^2-6x+4x-6 \\ \\4x^2-6x+4x-6 -24=0\\ \\4x^2-2x-30=0 \ \ / :2\\ \\2x^2-x-15=0 \\ \\a=2, \ b=-1 , c= -15
 
\Delta =b^2-4ac = (-1)^2 -4\cdot2\cdot (-15) = 1+120=121\\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2*2 }=\frac{ 1-11}{4}=\frac{-10}{4}=- \frac{5}{2} \\ \\x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2*2 }=\frac{ 1+11}{4}=\frac{12}{4}=3 \\ \\Use \ positive \ value \ of \ x : \\ \\ x =3


5 0
4 years ago
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