Answer:
Range is 3 <= g(x) <= 27.
Step-by-step explanation:
The range is the values of g(x) for the given domain.
When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.
When x = 4 g(x) = 3(4)^2 - 6(4) + 3 = 27.
Answer: 9
Step-by-step explanation:
i used math
Won’t it look the same because you are basically rotating it in a full circle
You are given h(t) = 64–16t^2.
You need to find h(1.25).
Set up:
h(1.25) = 64 - 16(1.25)^2
Take it from here.