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Sliva [168]
3 years ago
12

In the game of roulette, a wheel consists of 32 slots numbered 00, 0, 1, 2, . . . , 30. To play the game, a metal ball is spun a

round the wheel and is allowed to fall into one of the numbered slots. Complete parts (a) through (c).
(a) Determine the sample space. Choose the correct answer below.
A. The sample space is {00, 0, 1, 2, . . . , 30}.
B. The sample space is {00}.
C. The sample space is {00, 0}.
D. The sample space is {1, 2, . . . , 30}.
(b) Determine the probability that the metal ball falls into the slot marked 3 and Interpret this probability by choosing the correct answer below.
A. If the wheel is spun 100 times, it is expected about 31 of those times to result in the ball landing in slot 3.
B. If the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing not in slot 3.
C. If the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3.
(c) Determine the probability that the metal ball lands in an odd slot and Interpret this probability by choosing the correct answer below.
A. If the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.
B. If the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in an odd number.
C. If the wheel is spun 1,000 times, it
Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

(a) The sample space is {00, 0, 1, 2, . . . , 30}.

(b) If the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3.

(c) If the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.

Step-by-step explanation:

We are given that in the game of roulette, a wheel consists of 32 slots numbered 00, 0, 1, 2, . . . , 30.

To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots.

(a) The sample space is {00, 0, 1, 2, . . . , 30} which means the metal ball can land on any of these numbers.

(b) As we know that there is an equal probability of the metal ball landing on any of the slots marked in the sample space.

Total number of slots = 32

Number of slots marked with 3 = 1

So, the probability that the metal ball falls into the slot marked 3 is given by =  \frac{1}{32}  = 0.031 or 3.1%

This means that if the wheel is spun 100 times, it is expected about 3.1 of those times to result in the ball landing in slot 3.

So, if the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3 because (0.031 \times 1000) = 31.

(c) As we know that the odd slot in the given sample space is {1, 3, 5,......, 29}.

Total number of slots = 32

Number of odd slots = 15

So, the probability that the metal ball lands in an odd slot is given by =  \frac{15}{32}  = 0.47 or 47%.

This means that if the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.

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Answer:

Ernest gets 194 monthly allowance

Step-by-step explanation:

* Lets revise the rule of the average

- Average = The sum ÷ the total number

- Assume that the allowances money of Ernest, Jack, David and Mike

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∵ The average allowance money of Ernest jack David and mike is

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∴ 123 = (E + J + D + M) ÷ 4

- Multiply both sides by 4

∴ E + J + D + M = 492 ⇒ (1)

∵ The average allowance of Ernest jack and David is 159 per month

    per person

∴ 159 = (E + J + D) ÷ 3

- Multiply both sides by 3

∴ E + J + D = 477 ⇒ (2)

- Subtract equation(2) from equation (1) to find M

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* <em>Mike's monthly allowance is 15</em>

∵ David's monthly allowance is 2 less than mikes

∴ D = M - 2

∵ M = 15

∴ D = 15 - 2 = 13

∴ <em>David's monthly allowance is 13</em>

∵ Mikes monthly allowance is 1/18 of jacks

∴ M = \frac{1}{18} × J

∴ 15 = \frac{1}{18} × J

- Multiply both sides by 18

∴ J = 270

* <em>Jack's monthly allowance is 270</em>

- Substitute the values of D , J in equation (2) to find E

∵ D = 13 and J = 270

∵ E + J + D = 477

∴ E + 270 + 13 = 477

∴ E + 283 = 477

- Subtract 283 from both sides

∴ E = 194

* <em>Ernest's monthly allowance is 194</em>

*<em> Ernest gets 194 monthly allowance</em>

4 0
3 years ago
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