To solve for the time it reach the maximum height, you must solve the first derivative of the function and equate it to zero
<span>h(t) = −4.9t^2 + 14.7t + 1</span>
dh/ dt = -9.8t + 14.7
then equate to zero
-9.8t + 14.7 = 0
solve for t
t = 1.5 s
then the maximum height is when t = 1.5
<span>h(t) = −4.9t^2 + 14.7t + 1
h(1.5) = </span><span>−4.9(1.5)^2 + 14.7(1.5) + 1
h(1.5) = 12.025 m
</span>
(1.6x + 3.25) + (0.3x + 0.5)
combine like terms
1.6x+.3x +3.25 +.5
Result:
1.9 x + 3.75
Step-by-step explanation:
we have two lines you have to draw.
one is all in the bottom left quadrant (for x<=0) and one in the upper right quadrant (for x>5).
the easiest is for x>5. the line function is only
f(x) = y = 3
so, this is a horizontal line on the grid line for y = 3. it starts above x=5 and then goes all the way to the right ("to infinity and beyond !"). just, if possible, mark the starting point at x=5 as a little empty "circle" instead of a full dot, as x=5 is explicitly excluded (due to x>5).
and for x<=0 the line
f(x) = y = 4x - 3
goes sharp down but goes a little bit to the left the further down it goes. it starts with x=0, which gives y=-3 per the function.
so, the starting point (with a full dot, as x=0 is included) is (0,-3).
from there it goes sharp down and a little bit to the left.
for example the next point is for x=-1, which gives y=-7, so it is the point (-1,-7). x=-2 gives y=-11 and the point (-2,-11).
the line has to go through so these points and further down (again, "to infinity and beyond !"), as to move further left on the negative x-axis.
T= 1.272..
12.5t = 15.9
Therefore t= 1.272
Answer:
here's your answer buddy
Step-by-step explanation:
In LMN - LMO
LM=LM {common} S
NL=MO { given} S
LO=MN {given} S
therefore by SSS criteria we can say that triangle LMN=LMO
the above mentioned answer is 100% correct
so please don't doubt
mark as brainliest if you wish
thank you
