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lawyer [7]
3 years ago
13

What is the perimeter of Quadrilateral ABCDwith vertices at A(−11, −6), B(−3, 0), C(1, 0), and D(1, −6)?

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

32 units

Step-by-step explanation:

the perimeter =

(1 -(-3)) +(0-(-6)) + (1 -(-11) + (√(12-4)²+6²)

= (1+3) +(0+6) +(1+11) +(√(64+36))

= 4+6+12 + 10

=32 units

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Kitty [74]

Answer:

b. 4x-8

Step-by-step explanation:

1/2 x(8x-16)

= 1/2(8x) - 1/2 (16)

=4x - 8

Hope this helped

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Write as a single power of 9<br> 9^6 × 9^3 ÷ 9^4
bazaltina [42]

Answer:

9^5is the answer.

Step-by-step explanation:

(i)9^6×9^3=9^9 when we multiply we will add the power.

(ii) 9^9÷9^4= 9^5 when we divide we will subtract the power.

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Step-by-step explanation:

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Find the sum of the convergent series. (round your answer to four decimal places. ) [infinity] (sin(9))n n = 1
Alexus [3.1K]

The sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

For given question,

We have been given a series \sum_{n=1}^{\infty}~(sin(1))^n

\sum_{n=1}^{\infty}~(sin(1))^n=sin(1)+(sin(1))^2+...+(sin(1))^n

We need to find the sum of given convergent series.

Given series is a geometric series with ratio r = sin(1)

The first term of the given geometric series is a_1=sin(1)

So, the sum is,

= \frac{a_1}{1-r}

= sin(1) / [1 - sin(1)]

This means, the series converges to sin(1) / [1 - sin(1)]

\sum_{n=1}^{\infty}~(sin(1))^n

= \frac{sin(1)}{1-sin(1)}

= \frac{0.8415}{1-0.8415}

= \frac{0.8415}{0.1585}

= 5.31

Therefore, the sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

Learn more about the convergent series here:

brainly.com/question/15415793

#SPJ4

7 0
1 year ago
A circle has an area of 2290.221. What is the radius? (round to the nearest whole number)
erica [24]

Answer: 27

Step-by-step explanation:

use the formula for the area of circle and solve for r: A=pi r^2

2290.221=pir^2 <---divide by pi

729=r^2 <--- square root both sides

27=r

8 0
3 years ago
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