Answer:
The answer should be: B
I think it's B because there are 2 cups of water (2c) and 7 bottles of water (7w) which costs $16 so that would be 2c +7w=16. Also for the other one, it's 3 cups (3c) and 8 bottles of water (8W) and the cost is $19 so that would be
3c + 8w =19
Step-by-step explanation: Hope this helps and gl :))
Answer:
2.50 dollars.
Step-by-step explanation:
Given:
Will and his friends buy a large salad to share and several slices of pizza, p.
The graph given shows the total cost for lunch, c and slices of pizza,p.
p is marked horizontally, and c vertically.
Observing the points marked we find that for every increase of one slice of pizza, the cost i.e. c on vertical line increases by 0.50 times vertical grid.
Since each grid equals 5 dollars vertically, we find 1/2 grid increase is equal to increase of 1/2(5 ) =2.50 dollars.
Thus for increase of one slice of pizza, 2.50 dollars cost is increased.
Answer:
y = 7/5 x + 31
Step-by-step explanation:
To find the slope, we need to use the formula
m = (y2-y1)/(x2-x1)
m =(-4-17)/(5- -10)
= -21/(5+10)
= 21/15
Divide the top and bottom by 3.
= 7/5
The slope is 7/5.
Using the point slope form of the equation,
y-y1 = m(x-x1)
y-17 = 7/5 (x--10)
y-17 = 7/5(x+10)
Distribute the 7/5 ths.
y-17 = 7/5 x + 7/5*10
y-17 = 7/5 x +14
Add 17 to each side
y = 7/5 x + 14 + 17
y = 7/5 x + 31
This is in slope intercept form, with the slope being 7/5 and the y intercept of 31
Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631
20% x 50 =(20 / 100) x 50 = (20 x 50) / 100 = 1000 / 100 = 10
answer is 10
