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3 years ago

Can someone please help me

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

8 0

Answer: 19

Step-by-step explanation:

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Pls help no links in the answer

Dominik [7]

Answer:

Hello my friend, I hope this helps you!

Step-by-step explanation:

7 0

2 years ago

The function y = 8.5(1.1)x models the population in thousands of a town where x is the number of years after 2000. What will be

nikdorinn [45]

Answer:

The population will be at 65.45 in 2007.

Step-by-step explanation:

I graphed the equation below to find the answer.

If this answer is correct, please make me Brainliest!

6 0

3 years ago

Oscar was not safeguarding his personal identification and chose a two-digit PIN for his debit card using the numbers 0 - 9. Wit

ryzh [129]

There are 90 different identification numbers possible.

<h3>What are the permutation and combination?</h3>

In terms of mathematical concepts, “permutation” and “combination” are related to each other.

The combination is the counting of selections that we make from n objects.

Oscar was not safeguarding his personal identification and chose a two-digit PIN for his debit card using the numbers 0 - 9.

There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are;

10 × 10 = 100 total possible PINs.

Now, because you can't use the same number twice, we subtract 10 from 100 because there are 10 numbers that can match themselves.

100 -10 =90

Hence, there are 90 different identification numbers possible.

Learn more about combination here;

brainly.com/question/24138361

#SPJ2

5 0

2 years ago

Read 2 more answers

7(x-3)+6=5x-9 please solve the equation fully

TiliK225 [7]

Answer:

I love algebra anyways

The ans is x=3 steps is in the picture with the ans

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

4 0

2 years ago

What is the solution-|-x|=-12

andreev551 [17]

The solution to the equation includes both the positive and negative portions of the solution. x = 12, -12

7 0

3 years ago

Can someone please help me​

Can someone please help me