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Lelu [443]
4 years ago
12

N = Noekt

Mathematics
1 answer:
Travka [436]4 years ago
6 0

Answer:

Step-by-step explanation:

You wrote the formula incorrectly. It is, correctly:

N=N_0e^{-kt}

The k has to be a negative in the formula; if it's not, the time ends up as negative, which will NEVER be the case (unfortunately, time does not go backwards).

If the skeleton contains 67% of the C-14 it contained when the bird was alive, that 67 is our "N". When the bird was alive, it contained 100% of its C-14; soN_0 is 100. We know k, e is Euler's number, and we are looking for t.

67=100e^{-.0001t}

Begin by dividing both sides by 100 to get

.67=e^{-.0001t

To get that t out from its current exponential position, we take the natural log of both sides. We do this because 1. it's the only way to get an exponent down from that position and 2. because natural logs and e are inverses of each other; natural logs "undo" e's and e's "undo" natural logs.

ln(.67)=ln(e^{-.0001t}) Again, because e and ln undo each other:

ln(.67) = -.0001t and solve for t. Take the natural log of .67 on your calculator and get

-.4004775666 = -.0001t and

t = 4004.7 years

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Answer:

Each of the students absent for 1, 2, 4 and 5 days get 57, 53, 45 and 40 copies of the the reading books respectively.

Step-by-step explanation:

English Translation

The team of teachers from the Humanistic Training Area decides to distribute 195 copies of reading books to 4 students previously classified on their own merits. But the distribution will be made taking into account absences from classes during the first cycle. How many books does each student receive if their absences have been 1; two; 4 and 5 days, respectively?

Solution

Because the more the number of days absent, the less the number of books each of the 4 students deserve, we have to employ an elaborate scheme.

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Now, if we add another 48.75 copies of books to the total number of books, each person gets 60.9375 books.

But, we can then divide 48.75 extra books on top according to the number of days absent and subtract each person's number from the assumed 60.9375 books, with an extra 48.75 books.

Total number of days absent = 1 + 2 + 4 +5 = 12

(48.75/12) = -4.0625 copies for each absent day.

The student with only 1 absent day gets 60.9375 - 4.0625 = 56.875 copies = 57 copies

The student with 2 absent days, gets = 60.9375 - (2×4.0625) = 52.8125 copies = 53 copies

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Hence, each of the students absent for 1, 2, 4 and 5 days get 57, 53, 45 and 40 copies of the the reading books respectively.

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