Answer:
CPU is known as <u>Central</u><u> </u><u>Processing</u><u> </u><u>Unit</u><u>.</u>
Answer:
Digital communication technologies
Explanation:
connecting people across the globe has become easier and faster. Platforms such as Zoom, Room, Microsoft teams, WebEx, and many others are buzzing virtual world spaces to connect and share.
Answer:
The correct answer is (a) Remove the affected servers from the network.
Explanation:
Solution:
Now, since the organisation top priority is more of containment over eradication, an outbreak code that is hostile as an can be suppressed effectively by removing the web server completely from the over all network facilities or infrastructure.
Also, if the affected servers are not removed, it might affect the integrity, confidentiality of sensitive materials or documents which will be exposed to the outside world by the attacker.
Answer:
the user should disable file and print sharing on the laptop
Explanation:
According to my research on information technology and cyber security, I can say that based on the information provided within the question in order to prevent this the user should disable file and print sharing on the laptop. This is because this file and printer sharing allows users to see your files that you have available as shared and copy or print those files. Which if they are sensitive data you should just disable this option so that people on the same network cannot see or access these files.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
The answer is "2".
Explanation:
In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:
Given values:
Bandwidth = 64 kbps
Data frames = 512 bytes
Propagation Time (tp ) =270 ms
Change Bandwidth kbps to bps:
1 kb= 1024 bytes
calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps
1 bytes = 8 bits
512 bytes = 512 × 8 = 4096 bits
Frame length = 4096 bits
Formula
Transmission time (Tt) = Frame length /Bandwidth
Window size = 1+2a
where a = Propagation time/Transmission time
Calculate Transmission time:
Transmission time (Tt) = 4096 / 65536
Transmission time (Tt)= 625 m.sec
Calculate Window size:
Window size = 1+2(270/625)
Window size
= 1+2(0.432)
Window size
= 1+0.864
Window size = 1.864
Window size
= 2
