A LAN (local area network) is a group of computers and network devices connected together, usually within the same building. By definition, the connections must be high speed and relatively inexpensive (e.g., token ringor Ethernet). Most Indiana University Bloomington departments are on LANs.
A LAN connection is a high-speed connection to a LAN. On the IUB campus, most connections are either Ethernet (10 Mbps) or Fast Ethernet (100 Mbps), and a few locations have Gigabit Ethernet (1000 Mbps) connections.
A MAN (metropolitan area network) is a larger network that usually spans several buildings in the same city or town. The IUB network is an example of a MAN.
A WAN (wide area network), in comparison to a MAN, is not restricted to a geographical location, although it might be confined within the bounds of a state or country. A WAN connects several LANs, and may be limited to an enterprise (a corporation or an organization) or accessible to the public. The technology is high speed and relatively expensive. The Internet is an example of a worldwide public WAN.
Answer:
-3874₁₀ = 1111 1111 1111 1111 1111 1111 1101 1110₂
Explanation:
2's complement is a way for us to represent negative numbers in binary.
To get 2's complement:
1. Invert all the bits
2. Add 1 to the inverted bits
Summary: 2's complement = -N = ~N + 1
1. Inverting the number
3874₁₀ = 1111 0010 0010₂
~3874₁₀ = 0000 1101 1101₂
2. Add 1 to your inverted bits
~3874₁₀ + 1 = 0000 1101 1101₂ + 1
= 0000 1101 1110₂
You can pad the most signigicant bits with 1's if you're planning on using more bits.
so,
12 bits 16 bits
0000 1101 1110₂ = 1111 0000 1101 1110₂
They asked for double word-length (a fancy term for 32-bits), so pad the left-most side with 1s' until you get a total of 32 bits.
32 bits
= 1111 1111 1111 1111 1111 1111 1101 1110
Answer:
hi earlier u told me to answer ur question but i couldn't respond in the comments cos it said something went wrong
Explanation:
do i answer this question seriously or is this answer good?? srry im kinda dûmb T-T
The answer is a i looked up the question and it says a