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erastova [34]
3 years ago
6

Mr. Hermans's class is selling candy for a school fundraiser. their goal is to raise $500 by selling C boxes of candy. for every

box of candy they sell, they earn $2.75. Write and equation that the students could solve to figure out how many boxes they need to sell. Please answer quickly.
Mathematics
1 answer:
love history [14]3 years ago
4 0

2.75c ≥ 500

c ≥ 500 / 2.75

c ≥ 181.82

it should be greater than 181.82 to reach and get the target

So c should be like 182, 183, 184, and above

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A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
What is the area of the yellow region? INEED HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!
True [87]

Answer:

A=¼πr²

=¼(3.142×5²)

=19.64 square miles

8 0
3 years ago
The variable in a relation who’s value depends on the value of the independent variable is called what?
Viefleur [7K]
That is called the dependent variable. It depends upon the value of the independent variable.

f(x)=y

So we can see by inspection that the dependent variable y value depends upon the input value of the independent variable x

Any questions please feel free to ask. Thanks
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4 years ago
Write an expression that represents the area of only the red shaded region in terms of x
julsineya [31]

Answer:

(9 × 3x+7) - (5 × x+2)

Step-by-step explanation:

Red area

9 × 3x + 7

white area

5 × x+2

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3 pounds cost $15. How many pounds can you buy for $45?
morpeh [17]

Answer:

you can buy 9 poundssss

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