If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
brainly.com/question/15016913
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The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Sqrt(27)+sqrt(48)+sqrt(12)
Sqrt(27)=sqrt(3*3*3)=3*sqrt(3)
Sqrt(48)=sqrt(4*4*3)=4*sqrt(3)
Sqrt(12)=sqrt(2*2*3)=2*sqrt(3)
Add the three to get 9*sqrt(3)
Final answer:
9*sqrt(3)
Hope I helped :)
Answer:
7 pie is the world record. That is 1/4 under the record and your Answer.
Step-by-step explanation:
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