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4 years ago

14

John rolls a pair of six-sided number cubes.

1 answer:

Roman55 [17]4 years ago

8 0

Answer:

B. 2/3

Step-by-step explanation:

When you roll two dice, there are a total of 36 possible outcomes.

You need to find the number of outcomes whose sum is a multiple of 3. Then you need to find the number of outcomes whose sum is an odd number. Add these two numbers together and divide by 36.

Here are all the outcomes of rolling two dice. Each outcomes that has a multiple of 3 for the sum is in bold face. Each outcome that is odd is in <em>italic</em>. Some outcomes are both multiples of 3 and odd.

11 <em>12</em> 13 <em>14</em> 15 <em>16</em>

<em>21</em> 22 <em>23</em> 24 <em>25</em> 26

31 <em>32</em> 33 <em>34</em> 35 <em>36</em>

<em>41</em> 42 <em>43</em> 44 <em>45</em> 46

51 <em>52</em> 53 <em>54</em> 55 <em>56</em>

<em>61</em> 62 <em>63</em> 64 <em>65</em> 66

We are interested in any outcome that is a multiple of 3 or odd or both a multiple of 3 and odd.

We count the number of outcomes that are bold, italic, or both bold and italic.

The total is 24.

p(multiple of 3 or odd) = 24/26 = 2/3

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If a=i-2j and b= 2i - xj are parallel, then x is.....<br>a) 4 3 2 ) 2 d 4.

cupoosta [38]

Answer:

x = 4

Step-by-step explanation:

a = i-2j

b = 2i-xj

1 = k•2

-2 = k•(-x)

=> 1/2 = k

=> (-2)/(-x) = k

=> 1/2 = (-2)/(-x) => 1/2 = 2/x => x = 4

7 0

4 years ago

HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

tangare [24]

Answer:

$y=-(x-7)(x+3)$

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

$y=-(x+3)(x-7)$ but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is $y=a(x-h)^2+k$ .

This is called vertex form because it gives you the vertex is $(h,k)$ .

We are given that $(h,k)=(2,25)$ which makes our equation:

$y=a(x-2)^2+25$ .

We can find the value of $a$ by plugging in the x-intercept (7,0) for $(x,y)$ into:

$y=a(x-2)^2+25$

$0=a(7-2)^2+25$

$0=a(5)^2+25$

Subtract 25 on both sides:

$-25=a(5)^2$

$-25=a(25)$

Divide both sides by 25:

$\frac{-25}{25}=a$

$-1=a$ .

So the equation for the quadratic is:

$y=-1(x-2)^2+25$

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

$y=-1(x-2)(x-2)+25$

$y=-1(x^2-2x-2x+4)+25$

$y=-1(x^2-4x+4)+25$

$y=-x^2+4x-4+25$

$y=-x^2+4x+21$

Factor out -1:

$y=-(x^2-4x-21)$

WE need to find two numbers that multiply to be -21 and add to be -4:

$y=-(x-7)(x+3)$

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3 years ago

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satela [25.4K]

Answer:

1

Step-by-step explanation:

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3 years ago

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andreev551 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Kryger [21]

Answer:

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Step-by-step explanation:

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3 years ago