Question

A teacher wanted to know how well the gifted students in here class perform relative to her other classes. She administers a standardized test with a mean of 50 and a standard deviation of 10. A student scores of 55, what percent of students have a higher score than hers

Answer 1

Answer: 30.85%.

Step-by-step explanation:

Let X denotes the score of  random student.

Given: $\mu = 50$ and $\sigma=10$

We assume that scores are normally distributed.

Then , the probability that a a student score higher than 55:

$P(X>55)=P(\dfrac{X-\mu}{\sigma}>\dfrac{55-50}{10})\\\\=P(Z>0.5) \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z$

Hence, the percent of students have a higher score than hers is 30.85%.