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2 years ago

Will factor the express 36xyz + 24xy − 16x by dividing each term by a common fact

Mathematics

2 answers:

sesenic [268]2 years ago

6 0

$\\ \bull\tt\longmapsto 36xyz+24xy-16x$

Divide by 4

$\\ \bull\tt\longmapsto \dfrac{36xyz}{4}+\dfrac{24xy}{4}-\dfrac{16x}{4}$

$\\ \bull\tt\longmapsto 9xyz+6xy-4x$

Divide by x

$\\ \bull\tt\longmapsto \dfrac{9xyz}{x}+\dfrac{6xy}{x}-\dfrac{4x}{x}$

$\\ \bull\tt\longmapsto 9yz+6y-4$

MrMuchimi2 years ago

4 0

Answer:

4x(9yz + 6y - 4)

Step-by-step explanation:

36xyz + 24xy - 16x ← factor out 4x from each term

= 4x(9yz + 6y - 4)

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2 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

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$x=\sqrt{6}, y=-180$ inflection point

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Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

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2 years ago