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2 years ago

Will factor the express 36xyz + 24xy − 16x by dividing each term by a common fact

Mathematics

2 answers:

sesenic [268]2 years ago

6 0

$\\ \bull\tt\longmapsto 36xyz+24xy-16x$

Divide by 4

$\\ \bull\tt\longmapsto \dfrac{36xyz}{4}+\dfrac{24xy}{4}-\dfrac{16x}{4}$

$\\ \bull\tt\longmapsto 9xyz+6xy-4x$

Divide by x

$\\ \bull\tt\longmapsto \dfrac{9xyz}{x}+\dfrac{6xy}{x}-\dfrac{4x}{x}$

$\\ \bull\tt\longmapsto 9yz+6y-4$

MrMuchimi2 years ago

4 0

Answer:

4x(9yz + 6y - 4)

Step-by-step explanation:

36xyz + 24xy - 16x ← factor out 4x from each term

= 4x(9yz + 6y - 4)

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2 years ago

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OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

$\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}$

we need to simplify that

$x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)$

so we can continue

$\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}$

and we can put all together

$\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}$