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Nady [450]
4 years ago
8

A line passes through the point (3 comma 1 comma negative 8 )​, and is parallel to the vector 5 Bold i plus 3 Bold j plus 3 Bold

k. Find the standard parametric equations for the​ line, written using the components of the given vector and the coordinates of the given point.
Mathematics
1 answer:
motikmotik4 years ago
4 0

The line \ell passing through (3, 1, -8) and running parallel to the vector <5, 3, 3> has the vector equation

\ell=(3\,\vec\imath+\vec\jmath-8\,\vec k)+t(5\,\vec\imath+3\,\vec\jmath+3\,\vec k)

or

\ell=(3+5t)\,\vec\imath+(1+3t)\,\vec\jmath+(3t-8)\,\vec k

and from this we can extract a set of parametric equations for the line:

\begin{cases}x(t)=5t+3\\y(t)=3t+1\\z(t)=3t-8\end{cases}

where t\in\Bbb R.

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Answer:

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Step-by-step explanation:

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11.<br>The domain of f(x) is [4, 5, 6]. If f(x) = 3x + 2, what is the range?​
grigory [225]

Answer:

The range of the function is:

Range R = {14, 17, 20}

Step-by-step explanation:

Given the function

f(x) = 3x + 2

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We are given that the domain of the function is:

Domain D = {4, 5, 6}

Now,

substituting x = 4 in the function

f(4) = 3(4) + 2

f(4) = 12 + 2

f(4) = 14

substituting x = 5 in the function

f(5) = 3(5) + 2

f(5) = 15 + 2

f(5) = 17

substituting x = 6 in the function

f(6) = 3(6) + 2

f(6) = 18 + 2

f(6) = 20

Thus, we conclude that:

at x = 4, y = 14

at x = 5, y = 17

at x = 6, y = 20

Thus, the range of the function is:

Range R = {14, 17, 20}

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