Question

( PLEASE HELP) The points (3,-2) (-3,-2) and (-3,6) are the vertices of a triangle. Find the perimeter of the triangle. (Hint: Use the Pythagorean theorem to find the length of the hypotenuse.

Answer 1

Look at the picture.

$x^2=6^2+8^2\\\\x^2=36+64\\\\x^2=100\to x=\sqrt{100}\to x=10$

The perimeter of the triangle:

$P_\Delta=6+8+10=24$