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Flauer [41]
3 years ago
7

How to find the variables of the angles

Mathematics
1 answer:
34kurt3 years ago
8 0

Answer:

y=23

x=28

Step-by-step explanation:

3y=2x+13

8y-4=180

basic algebra, solve 2nd equation then substitute

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Step-by-step explanation:

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3 years ago
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UNO [17]

Answer:

a) 8 b)9 c)1 d) 3

Step-by-step explanation:

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3 years ago
NEED THESE ANSWERED ASAP SO I CAN GRADUATE THIS WEEK
babunello [35]

For this case we must solve each of the equations proposed:

A) -6 (2s-1) = 30

We apply distributive property to the terms within parentheses:

-12s + 6 = 30

Subtracting 6 from both sides of the equation we have:

-12s = 24

Dividing between -12 on both sides of the equation:

s = \frac {24} {- 12}s = -2

B) -3m = -5 (m-8)

We apply distributive property to the terms within parentheses:

-3m = -5m + 40

We add 5m on both sides of the equation:

2m = 40

Dividing between 2 on both sides of the equation:

m = \frac {40} {2}\\m = 20

C) 7 (2-g) = 49

We apply distributive property to the terms within parentheses:

14-7g = 49

We subtract 14 from both sides of the equation:

-7g = 35

Dividing between -7 on both sides of the equation:

g = \frac {35} {- 7}\\g = -5

D) -7 (3w + 4) = 14

We apply distributive property to the terms within parentheses:

-21w-28 = 14

We add 28 to both sides of the equation:

-21w = 42

Dividing between -21 on both sides of the equation:

w = \frac {42} {- 21}\\w = -2

Answer:

s = -2\\m = 20\\g = -5\\w = -2

6 0
3 years ago
Read 2 more answers
C 4. What is the simplified form of 345e 15c ?<br>b) 6c<br>9 se' 43<br>15c 5<br>4) 12a
levacccp [35]
I think it is b but no positive

8 0
3 years ago
A card is drawn from a standard deck of 52 playing cards. If the card is a club, a fair coin is flipped 9 times and the number o
olasank [31]

Answer: There are 18 elements in the sample space for this experiment

Step-by-step explanation:

Total cards = 52

Total outcomes on tossing a coin = 2   [1 head , 1 tail]

If the card is a club, a fair coin is flipped 9 times and the number of heads flipped is noted (but card drawn is not noted)).

Possible outcomes for heads = 0,1,2,...,9

So sample space for this event = {0,1,2,3,4,5,6,7,8,9} <em> </em><em> (Total </em><em>10 elements</em><em> ) </em><em> (i)</em>

If it is not a club, the coin is only flipped 3 times, but this time the result of each flip is noted(but card drawn is not noted).

Sample space with all possible outcomes ={TTT,TTH, THT, HTT, HTH,HHT,THH,HHH}   <em> (Total </em><em>18 elements</em><em> )  </em><em>(ii)</em>

<em />

From (i) and (ii), Total elements in the sample space for this experiment = 10+8 = 18

Hence, there are 18 elements in the sample space for this experiment

4 0
3 years ago
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