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o-na [289]
4 years ago
11

3(x -2) >-3 Solve each inequality.

Mathematics
1 answer:
wolverine [178]4 years ago
8 0
-3 that should be right
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PLEASE HELP? SERIOUSLY? :)
IRINA_888 [86]
2x + 5y = -8 . . . (1)
-133x - 4y = -8 . . . (2)

(1) * 4 => 8x + 20y = -32 . . . (3)
(2) * -5 => -665x + 20y = 32 . . . (4)

(3) - (4) => 673x = 0
x = 0
From (1), 2(0) + 5y = -8
5y = -8
y = -8/5
3 0
3 years ago
How Do these two equations compare?<br><br> 2x + 10 = 16. 2x- 10 = 16
finlep [7]
In 2x+10=16, x will equal 3. In 2x-10=16, x will equal 13.
6 0
3 years ago
The dinner bill came to $72.48, and Julio tipped the waiter 15%. What is the total price of dinner?​
balu736 [363]

Answer:

It is 83.35 Unless your rounding up then it is 84 dollars

Step-by-step explanation:

5 0
3 years ago
Which of the binomials below is a factor of this trinomial? ---- PLS EXPLAIN FOR ME?
Dennis_Churaev [7]
To factor this notable trinomial, you have to find two numbers that summes give -5 and multiplied give 6*(-25) = -150

Then let's call n1 and n2 the two numbers and a the number before x^2 (6)

ax^2+sx+fn = (ax + n1)(x + n2/a)

Numbers are -15 and +10

-15+10 = -5
-15*10 = -150

So

(6x-15)(x + 10/6)

Or write it as a sum

6x^2 + 10x - 15x - 25

And factor

6x^2 + 10x = 2x(3x+5)

-15x-25 = -5(3x+5)

(2x-5)(3x+5)
5 0
4 years ago
Read 2 more answers
Misaka solved the radical equation x – 3 = square root of 4x-7 but did not check her solutions. (x – 3)2 = square root of 4x-7^2
Minchanka [31]

Answer:

x=8 is a true solution of the radical equation

Step-by-step explanation:

we have

x-3=\sqrt{4x-7}

Solve for x

squared both sides

(x-3)^{2}=4x-7\\\\x^{2}-6x+9=4x-7\\\\ x^{2}-10x+16=0

Convert to factored form

x^{2}-10x+16=(x-2)(x-8)

The solutions are x=2 and x=8

<u><em>Verify the solutions</em></u>

For x=2

Substitute in the original equation

2-3=\sqrt{4(2)-7}

-1=1 ----> is not true

therefore

x=2 is not a true solution of the radical equation

For x=8

Substitute in the original equation

8-3=\sqrt{4(8)-7}

5=5 ----> is true

therefore

x=8 is a true solution of the radical equation

3 0
4 years ago
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