C.
Water vapor is the "fuel" for the hurricanes because it releases the "latent heat of condensation" when it condenses to form clouds and rain, warming the surrounding air. (This heat energy was absorbed by the water vapor when it was evaporated from the warm ocean surface, cooling the ocean in the process
The condition of being physically fit and active
The answer is C. Amniotic membrane. It is the <span>Amniotic membrane that surrounds and protects the embryo. It is the innermost layer of the placenta. it consist thick basement of membrane that protects the embryo from any possible harm.
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We are well aware that there are two stages of photosynthesis:
- Light dependent reactions
- Light independent reactions/ Calvin cycle/ dark reactions.
Calvin cycle or light-independent reactions:
This comprise the process during which carbon dioxide enters into the leaves of plants and passes through series of steps to form sugar or food. This process depends on the supply of ATP, (the ATP that is formed previously during light dependent reactions).
Now there are three stages of Calvin cycle:
- 1) carbon fixation
- 2) reduction
- 3) regeneration
During the process of carbon fixation CO2 combines with a 5-carbon compound called RuBP or ribulose-1,5-bisphosphate which results in the synthesis of a 6-carbon compound that splits up in to 2 three carbon compounds called phosphoglyceric acid (3-PGA).
Here out focus will be the process of Reduction.
Reduction is the second stage of Calvin cycle during which phosphoglyceric acid (3-PGA) is converted to glyceraldehyde-3-phosphate (G3P) that is a sugar. During the process of reduction, energy in the form of ATP and NADPH are used for the conversion of 3-PGA to G3P. As 3-PGA is reduced to G3P, therefore this process is known as reduction.
After reduction, a series of reactions occur that lead to the synthesis of glucose but since focus of our question was reduction, so you can see more details of the process in attached figure.
Hope it helps!
Answer:
In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:
• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day
• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0
• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day
• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day
So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.
