Answer:
Please find the solution in the image attached below.
Step-by-step explanation:
Tcos60 -2T sin(90-theta) = 0
Tcos60 = 2T(cos theta)
cos 60 = 2cos theta
cos60 = 2cos theta
1/4 = cos theta
theta = 75.5
So the angle to the vertical = 90-75.5 = 14.5
S
Resolving perpendicular
Tsin60 + 2Tsin75.5 - 2g = 0
T(sin 60 + 2sin75.5) = 2g
T = 19.6/sin 60 + 2sin75.5
T = 19.6/1.936 + 0.866
T = 19.6/2.802 = 7.0N
Hope this helps!
Answer:
x= 27
Step-by-step explanation:
Move <u>constant</u> to the right-hand side and change its sign.
= 2+6
Add the numbers.
= 8
Square both sides of the equation.
2x+10= 64
Move the <u>constant</u> to the right-hand side and change its sign.
2x= 64-10
Subtract the numbers.
2x= 54
Divide both sides of the equation by 2.
x= 27
We know that the original width was 5, and that after the enlargement the width is 45. To calculate the scale factor we divide the final width between the original one, then:
Therefore the scale factor is 9.