3 years ago

What is the solution of the system for 1-3?

Mathematics

1 answer:

Aloiza [94]3 years ago

4 0

Answer:

Step-by-step explanation:

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Which ordered pairs make both inequalities true? Check all that apply.

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the area of the triangle formed by points of intersection of parabola y=a(x-3)(x+2) with the coordinate axes is 10. find a if it

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15a=12

a= 4/5

Step-by-step explanation:

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3/4 divided by 5/6? i need the answer for this mobymax thing if i dont gets it done, im screwed

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Sin(60-theta)sin(60+theta)

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Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

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It's possible to build a triangle with a side lengths of 5, 5, and 10

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