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2 years ago

Somebody pls help I’m doin a exam!!!!

Mathematics

2 answers:

Lynna [10]2 years ago

8 0

Answer:

x=2

y= -3

Step-by-step explanation:

3x+2y=0 2y=-3x, y=-3x/2

3x-15y=51

substitute y

3x-15(-3x/2)=51

3x+45x/2=51

multiply by 2

6x+45x=102

51x=102

x=2

y= -3

gregori [183]2 years ago

6 0

Answer:

x=2

y=-3

Step-by-step explanation:

Ok so....

Since this problem is practically set up all you have to do is solve it! So what i did was try to cancel both of the x's so that I am just left with the y. I subtract everything and end up with

17y = -51

Now, all you have to do is divide giving you the answer for y which is

y = -3

Next, you have to plug in the value of y to either the first equation or second equation in the question. I chose the first equation and once I plugged it in it looked like this.

3x - 6 = 0

Now, add 6 to both sides giving you

3x = 6

Now all you have to do is divide

x = 2

TAADAA!!!

If you want to check your answer if you're unsure just plug in both values to either the first equation or second equation in the original problem. Okay well have a good day!! :D

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Svetlanka [38]

I say that the answer is 7 bc it’s -8+15

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2 years ago

Read 2 more answers

Please help me, i will give brainliest!! help me please

Minchanka [31]

The answers are :

10) 25 : 24

11) 24 : 5

12) 36 : 5

13) 7 : 3

14) 15 : 1

Ratio = Number of event 1 : Number of event 2 (in same unit, if necessary)

10

Girls preferring orange juice : Boys preferring orange juice

50 : 48 (Divide by 2 on both sides)

25 : 24

11

Boys preferring orange juice : Boys preferring grapefruit juice

48 : 10 (Divide by 2 on both sides)

24 : 5

Remember :

1 minute = 60 seconds
1 week = 7 days
1 hour = 60 minutes

12

3 minutes : 25 seconds

3 × 60 : 25 (Divide by 5 on both sides)

3 × 12 : 5

36 : 5

13

2 weeks : 6 days

2 × 7 : 6 (Divide by 2 on both sides)

7 : 3

14

5 hours : 20 minutes

5 × 60 : 20 (Divide by 20 on both sides)

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15 : 1

4 0

1 year ago

what is the correct upper and lower control limits for 8.42 pounds and the accectable range for plus or minus .65 pounds

sweet [91]

Answer:

9.07 and 7.77 respectively.

Step-by-step explanation:

To determine the upper control limit, add 0.65 lb to 8.42 lb, obtaining 9.07 lb.

To determine the lower one, subtract 0.65 lb from 8.42 lb, obtaining 7.77 lb.

7 0

3 years ago

Find a set of parametric equations for y= 5x + 11, given the parameter t= 2 – x

Sati [7]

Answer:

$x = 2-t$ and $y = -5\cdot t +21$

Step-by-step explanation:

Given that $y = 5\cdot x + 11$ and $t = 2-x$ , the parametric equations are obtained by algebraic means:

1) $t = 2-x$ Given

2) $y = 5\cdot x +11$ Given

3) $y = 5\cdot (x\cdot 1)+11$ Associative and modulative properties

4) $y = 5\cdot \left[(-1)^{-1} \cdot (-1)\right]\cdot x +11$ Existence of multiplicative inverse/Commutative property

5) $y = [5\cdot (-1)^{-1}]\cdot [(-1)\cdot x]+11$ Associative property

6) $y = -5\cdot (-x)+11$ $\frac{a}{-b} = -\frac{a}{b}$ / $(-1)\cdot a = -a$

7) $y = -5\cdot (-x+0)+11$ Modulative property

8) $y = -5\cdot [-x + 2 + (-2)]+11$ Existence of additive inverse

9) $y = -5 \cdot [(2-x)+(-2)]+11$ Associative and commutative properties

10) $y = (-5)\cdot (2-x) + (-5)\cdot (-2) +11$ Distributive property

11) $y = (-5)\cdot (2-x) +21$ $(-a)\cdot (-b) = a\cdot b$

12) $y = (-5)\cdot t +21$ By 1)

13) $y = -5\cdot t +21$ $(-a)\cdot b = -a \cdot b$ /Result

14) $t+x = (2-x)+x$ Compatibility with addition

15) $t +(-t) +x = (2-x)+x +(-t)$ Compatibility with addition

16) $[t+(-t)]+x= 2 + [x+(-x)]+(-t)$ Associative property

17) $0+x = (2 + 0) +(-t)$ Associative property

18) $x = 2-t$ Associative and commutative properties/Definition of subtraction/Result

In consequence, the right answer is $x = 2-t$ and $y = -5\cdot t +21$ .

5 0

2 years ago

Can someone please help me factor and write the equations for these two problems ?

prisoha [69]

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = $\frac{3x}{x^2-3x-10}$

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

= x(x - 5) + 2(x - 5)

= (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = $\frac{3x}{(x + 2)(x - 5)}$

Asymptotes 4

h(x) = $\frac{(x-5)}{x^{2} + 14x + 40}$

= $\frac{x-5}{x^{2}+10x+4x+40}$

= $\frac{x-5}{x(x+10)+4(x+10)}$

= $\frac{x-5}{(x+10)(x+4)}$

5 0

2 years ago