All categories

4 years ago

What is 33/8 as a mixed fraction

Mathematics

2 answers:

nlexa [21]4 years ago

7 0

Answer:

4 1/8

Step-by-step explanation:

You would divide 33 by 8 with a remainder, no need to make it a decimal. That would equal 4 with a remainder of 1. Therefore, the mixed fraction/number would be 4 1/8. Hope this helps! :)

Inga [223]4 years ago

6 0

Answer:

4 1/8

Step-by-step explanation:

First see how many times 8 goes into 33 which is 4 so that's your whole number 8x4 is 32 so there will be one left over which is your numerator and 8 stays the same as your denominator.

Hope this makes sense!

You might be interested in

The ages of a sample of fans at a rock concert are listed. 24, 27, 19, 21, 18, 23, 21, 20, 19, 33, 30, 29, 21, 18, 24, 26, 38, 1

Rudik [331]

Answer:

1. {18, 18 , 19 , 19 , 19 , 20 , 21 , 21 , 21 , 21 , 23 , 24 , 24 , 26 , 27 , 27 , 29 , 30 , 30 , 30 , 33 , 33, 34 , 35 , 38 }

2a) md= 24 b) Q1=20.5 c) Q3= 30 3) Q3-Q1 =9.5 b) 19/48

Step-by-step explanation:

To answer this question the 1st and the 2nd we need to order the data entries. So from ordering from the lowest to the highest value:

1. {18, 18 , 19 , 19 , 19 , 20 , 21 , 21 , 21 , 21 , 23 , 24 , 24 , 26 , 27 , 27 , 29 , 30 , 30 , 30 , 33 , 33, 34 , 35 , 38 }

2. There are 25 entries.

{18, 18 , 19 , 19 , 19 , 20 , 21 , 21 , 21 , 21 , 23 , 24 , 24 , 26 , 27 , 27 , 29 , 30 , 30 , 30 , 33 , 33, 34 , 35 , 38 }

In odd quantities of observations, the Median equally separates it two parts.

md=24

b) To find out the 1st quartile, we can use this way:

$Q_{1}=\frac{i}{4}(n+1)\\ Q_{1}=\frac{1}{4}(25+1)\\ Q_{1}=\frac{1}{4}(26)=6.5$

Then 6.5 is between the 6th and 7th position. Let's find the mean of them, now:

$Q_1=\frac{20+21}{2}= 20.5$

c) Similarly toThe Third Quartile or Upper Quartile

$Q_{3}=\frac{i}{4}(n+1)\\ Q_{3}=\frac{3}{4}(25+1)\\ Q_{1}=\frac{3}{4}(26)=19.5$

The 19th position and 20th position average is: $\frac{30+30}{2} =30$

a) To find the Interquartile Range, we just need to find out the difference of the upper quartile and the lower one: $[tex](Q_3-Q_1)$ Q_3-Q_1[/tex]

(30-20.5)=9.5

b) Interquartile Ratio is given by the quotient of the Interquartile Range over the Median

$\frac{IQR}{md}=\frac{9.5}{24}=\frac{19}{48}$

4) Since the Relative frequency Histogram asked is a one with 7 classes. Let's calculate how many values.

k=1+3.32logn

7=1+3.32logn

6=3.32logn

n≈66

Each class must have an interval of 10 ages, for (91-18)/7≈ 10. Notice the orange line intercepts the midpoint of each interval.

4 0

4 years ago

please answer this question fast and please show all your work because I am locking for how can you do it please

inysia [295]

Option C is the correct values of the relationship between the number of cakes the baker makes and the number of bags of flour uses.

Solution:

Option A: Ratio of cakes baked to bags of flour used

$$\frac{9}{4}, \frac{18}{6}=\frac{3}{1} \text { and } \frac{27}{9}=\frac{3}{1}$

Here the ratios are not same.

So, this option is not true.

Option B: Ratio of cakes baked to bags of flour used

$$\frac{6}{2}=\frac{3}{1}, \frac{12}{4}=\frac{3}{1} \text { and } \frac{18}{6}=\frac{3}{1}$

Here the ratios are same.

So, this option is true.

Option C: Ratio of cakes baked to bags of flour used

$$\frac{4}{9}, \frac{6}{18}=\frac{1}{3} \text { and } \frac{9}{17}$

Here the ratios are not same.

So, this option is not true.

Option D: In this table cakes baked is 6 and the bags of flour is 18.

But a baker made 18 cakes using 6 bags of flour.

So, this option is not true.

Hence option C is the correct values of relationship between the number of cakes the baker makes and the number of bags of flour uses.

6 0

3 years ago

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

7 0

3 years ago

An employees hourly wage is $16.50 per hour plus $0.25 for each of the q units produced during the hour. Write an algebraic expr

shusha [124]

Answer:

16.50+0.25q

I need more words to make it so I can turn in the answer

4 0

3 years ago

A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why

VLD [36.1K]

Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

$Area=length\times width$ square units