Answer:
a) 560 (as you know)
Step-by-step explanation:
There are 7C3 = 35 ways to choose 3 full-time days from 7.
There are 2^4 = 16 ways to choose a half-day each day from the remaining 4 days.
The total number of possible schedules is ...
35×16 = 560
_____
nCk = n!/(k!(n-k)!)
7C3 = 7·6·5/(3·2·1) = 7·5 = 35
Answer:
Yes and no nor
Step-by-step explanation:
This problem is very simple. All you have to do is add 10 and 9. The correct answer is D.
Answer:
10
Step-by-step explanation:
To figure the mean, add up the numbers, 3+3+6+7+9+12+12+19=71 then divide it by the number of data points 71/7=10.1428571, I rounded it to 10.
